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babunello [35]
2 years ago
13

An ice cream parlor sells milkshakes in various sizes:

Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
7 0
No it is not a linear equation...in order for it to be linear it must be a straight line, but this line is curved slightly which prevents the pattern from being linear
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ASAP Help me please!!
Anvisha [2.4K]
<h3>Answer:  x = 14</h3>

=============================================

Work Shown:

Refer to the diagram below. I've added a line segment and two variables y and z. This forms two isosceles triangles.

The central angle 56 degrees subtends the same arc as the inscribed angle y. By the inscribed angle theorem, this means y = 56/2 = 28. The inscribed angle is always half of the central angle (when both angles subtend the same arc).

Focus on the smaller isosceles triangle that has angles 56, z and z. Those three angles add to 180

z+z+56 = 180

2z+56 = 180

2z = 180-56

2z = 124

z = 124/2

z = 62

Now focus on the larger isosceles triangle (angles y = 28, x+z and x+z)

We'll use the same trick as before.

(x+z)+(x+z)+(y) = 180

(x+62)+(x+62)+(28) = 180 ... plug in z = 62 and y = 28

2x+152 = 180

2x = 180-152

2x = 28

x = 28/2

x = 14

7 0
2 years ago
9/11 ÷ 5/11 = a b/c =
stepan [7]

9/11 / 5/11

= 9/11 * 11/5

= 9/5

= 1 4/5

5 0
3 years ago
Read 2 more answers
HELP PLS MY MOM IS GONNA BE MADDDD
aliya0001 [1]

5/8 ÷ 1/4

5/8 • 4/1

5/2

7 0
2 years ago
Read 2 more answers
Help me plleaaaseeee
polet [3.4K]

Answer: B

Reason:

44 + x  \geq 66

x \geq  22

Also when we have a greater and equal to sign (\geq), it will be a filled in circle.

Thats why its by.

4 0
2 years ago
Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0
Arada [10]

Answer:

b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0

Step-by-step explanation:

The given matrix addition is

B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

We need to find the elements of matrix B.

Let B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}

Substitute the value of matrix.

\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

After addition of two matrix we get

\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

On equating both sides.

b_{11}+15=1\Rightarrow b_{11}=-14

b_{12}-7=2\Rightarrow b_{12}=9

b_{13}+4=12\Rightarrow b_{13}=8

b_{21}+0=4\Rightarrow b_{21}=4

b_{22}+1=0\Rightarrow b_{22}=-1

b_{23}+2=2\Rightarrow b_{23}=0

Therefore, the elements of matrix B are b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0.

3 0
3 years ago
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