An ice cream parlor sells milkshakes in various sizes:

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

7 0

No it is not a linear equation...in order for it to be linear it must be a straight line, but this line is curved slightly which prevents the pattern from being linear

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Given: m∠AOC = 120°, m∠BOD = 150°. Find: m∠BOC.

Molodets [167]

angleBOC = 270°

All 3 angles meet at O thus

angleBOC = angle AOC + angle BOD = 120° + 150° = 270°

8 0

3 years ago

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zheka24 [161]

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$\bf (\stackrel{a}{\sqrt{3}}~,~\stackrel{b}{1i})\qquad \begin{cases} r=&\sqrt{(\sqrt{3})^2+1^2}\\ &\sqrt{3+1}\\ &2\\ \theta =&tan^{-1}\left( \frac{1}{\sqrt{3}}\right)\\\\ &tan^{-1}\left( \frac{\sqrt{3}}{3} \right)\\ &\frac{\pi }{6} \end{cases}~\hfill \implies ~\hfill 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right]$

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$\bf \left[ 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right] \right]^3\implies 2^3\left[ cos\left( 3\cdot \frac{\pi }{6}\right) +i~sin\left( 3\cdot \frac{\pi }{6}\right) \right] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 8\left[cos\left( \frac{\pi }{2} \right) +i~sin\left( \frac{\pi }{2} \right) \right]~\hfill$