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2 years ago

please help! easy science! second pic is the question and possible answers (A B C or D) its one question! brainliest promised!

Physics

1 answer:

kirza4 [7]2 years ago

4 0

Answer:

Please do not take my word for this at all, but this is what I found, "When the pendulum swings back down, the potential energy is converted back into kinetic energy. At all times, the sum of potential and kinetic energy is constant." So I think the answer is B also you are anime fan too lol :DD I love hinata

Explanation:

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Suppose that the magnetic field in some region has the form B = kz ˆx (where k is a constant). Find the force on a square loop (

AleksAgata [21]

Answer:

$F = ika^2$

Explanation:

As we know that loop is placed in YZ plane and magnetic field is along x direction

So here net force on the side of the loop which lies along Y axis is given as

$F_1 = i (\vec L \times \vec B)$

here we know that on Y axis z = 0

so B = 0

so we have

$F_1 = 0$

now on the opposite side we have z = a

so magnetic field is given as

$B = ka$

so force on that side is given as

$F = i(\vec L \times \vec B)$

$F = i(a)(ka) sin90$

$F_2 = ika^2$

so net force on the loop is given as

$F = F_1 + F_2$

$F = ika^2$

5 0

3 years ago

A tuba may be treated like a tube closed at one end. If a tuba has a fundamental frequency of 88.4 Hz, determine the first three

yulyashka [42]

Answer with Explanation:

We are given that

Fundamental frequency,f=88.4 Hz

Speed of sound,v=343 m/s

We have to find the first three overtones.

Tube is closed

The overtone of closed pipe is equal to odd number of fundamental frequency.

Therefore, the overtone of tuba

$f'=nf$

Where n=3,5,7,..

Substitute n=3

$f'=3\times 88.4=265.2Hz$

For second overtone

$f'=5\times 88.4=442Hz$

For third overtone

$f'=7\times 88.4=618.8Hz$

4 0

3 years ago

Starting from rest, a 2-m-long pendulum swings from an angleof

Andrews [41]

Answer:

D.) 1m/s

Explanation:

Assume the initial angle of the swing is 12.8 degree with respect to the vertical. We can calculate the vertical distance from this initial point to the lowest point by first calculate the vertical distance from this point the the pivot point:

$L_1 = L*cos(12.8) = 2*0.975 = 1.95 m$

where L is the pendulum length

The vertical distance from the lowest point to the pivot point $L_2$ is the pendulum length 2m

this means the vertical distance from this initial point to the lowest point is simply:

$L_3 = L_2 - L_1 = 2 - 1.95 = 0.05 m$

As the pendulum travel (vertically) from the initial point to the bottom point, its potential energy is converted to kinetic energy:

$E_p = E_k$

$mgh = mv^2/2$

where m is the mass of the pendulum, g = 10 m/s2 is the constant gravitational acceleration, h = 0.05 is the vertical it travels, v is the pendulum velocity at the bottom, which we are trying to solve for.

The m on both sides of the equation cancel out

$v^2 = 2gh = 2*10*0.05 = 1$