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Alexus [3.1K]
3 years ago
11

How far (in meters) will you travel in 3 minutes running at a rate of 6 m/s?

Physics
1 answer:
trasher [3.6K]3 years ago
7 0
The formula for distance is speed times time.

So 3 times 6 would be 18 m/s
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An objects motion changes
NARA [144]

Answer:

uh finish the question please lol.

3 0
3 years ago
Which tuning forks will give rise to a beat frequency of 20 Hz when sounded together with a 240 Hz tuning fork?
Lubov Fominskaja [6]

Use the concept of beat frequency to find the applicable final freqeuncy for 20Hz beat frequency.

Beat can be defined as 'the interference pattern between two sounds of slightly different frequencies0

The expression for beat frequency is given as

f_{beat} = |f_1-f_2|

Where,

f_2 = Final frequency

f_1 = Initial frequency

The beat frequency for us is 25Hz and the initial frequency is 240Hz, then

20= |f_2-240|

Being an absolute value, two values are possible, both in addition and subtraction:

f_2 = 240 \pm 20

The two possible values are

f_2 = 220Hz

f_2 = 260Hz

3 0
3 years ago
Your teacher (175kg) and the lab (15kg) are 2m apart. What is the gravitational force between them? Draw a FBD, and label
Pachacha [2.7K]
The gravitational force between two objects is given by
F=G \frac{m_1 m_2 }{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

In this problem, m_1 = 175 kg, m_2 =15 kg and r=2 m, therefore the gravitational force between the two objects is
F=(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}) \frac{(175 kg)(15 kg)}{(2m)^2}=4.38 \cdot10^{-8} N
7 0
3 years ago
Planet A takes one year to go around the sun at a distance at a distance of one A U.. Planet B is three A U. from the sun. How m
kotykmax [81]
I would take roughly around 3 years
4 0
3 years ago
A thin taut string is fixed at both ends and stretched along the horizontal x-axis with its left end at x = 0. It is vibrating i
Fofino [41]

Answer:

(a) Wavelength is 0.436 m

(b) Length is 0.872 m

(c) 11.518 m/s

Solution:

As per the question:

The eqn of the displacement is given by:

y(x, t) = (1.22 cm)sin[14.4 m^{- 1}x]cos[(166\ rad/s)t]          (1)

n = 4

Now,

We know the standard eqn is given by:

y = AsinKxcos\omega t           (2)

Now, on comparing eqn (1) and (2):

A = 1.22 cm

K = 14.4 m^{- 1}

\omega = 166\ rad/s

where

A = Amplitude

K = Propagation constant

\omega = angular velocity

Now, to calculate the string's wavelength,

(a) K = \frac{2\pi}{\lambda}

where

K = propagation vector

\lambda = \frac{2\pi}{K}

\lambda = \frac{2\pi}{14.4} = 0.436\ m

(b) The length of the string is given by:

l = \frac{n\lambda}{2}

l = \frac{4\times 0.436}{2} = 0.872\ m

(c)  Now, we first find the frequency of the wave:

\omega = 2\pi f

f = \frac{\omega}{2\pi}

f = \frac{2\pi}{166} = 26.42\ Hz

Now,

Speed of the wave is given by:

v = f\lambda

v = 26.419\times 0.436 = 11.518\ m/s

4 0
3 years ago
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