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MakcuM [25]
2 years ago
12

A rocket is fired at 100 m/s at an angle of 37, what was its speed at the top of its path?

Physics
1 answer:
Nadusha1986 [10]2 years ago
4 0

Answer:

0m/s

Explanation:

Since its fired at an angle, at the top there will be a split second where the velocity will be 0, as it has a parabolic shape, so the speed at the top of its path is 0

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Read 2 more answers
Spaceship 1 and spaceship 2 have equal masses of 300 kg. spaceship 1 has a speed of 0 m/s, and spaceship 2 has a speed of 6 m/s.
Kipish [7]

The final speed is 3 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces, the total momentum of the two spaceships must be conserved. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v

where

m_1 = m_2 = 300 kg is the mass of each spaceship

u_1 = 0 m/s is the initial velocity of spaceship 1

u_2 = 6 m/s is the initial velocity of spaceship 2

v is the combined velocity of the two spaceships after the collision

Solving for v, we find

v=\frac{m_2 u_2}{m_1+m_2}=\frac{(300)(6)}{300+300}=3 m/s

So, their final speed is 3 m/s.

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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