1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brrunno [24]
3 years ago
12

B) Complete the frequency polygon

Mathematics
1 answer:
masya89 [10]3 years ago
7 0

Could you explain this better. Maybe in a picture or better format?

You might be interested in
What is 3,150 simplified
Zinaida [17]
3,150 doesn't need to be simplified. so, i guess if it were to be simplified, it would just stay the same.
8 0
3 years ago
The expression (3z2) (2z4) is equivalent to which of the following numerical expression? A. 6z8 B. 6z6 C. 5z6 D. 5z8
balandron [24]
B.6z6
When you multiply with exponents you add the exponents together 4+2=6
Then just multiply the #s 2×3=6
7 0
3 years ago
Read 2 more answers
The reason we solve systems of equation is to find where the equation
muminat

Answer:

Yes

Step-by-step explanation:

Good luck

7 0
3 years ago
A scientist needs 10 L of a solution that is 60% acid. She has a 50% acid solution and a 90% acid solution she can mix together
dybincka [34]

Allegation is a method to find the ratio in which two or more indignant are mixed to produce a mixture or solution.

The equation represents the total liters of acid that are needed is,

0.5x+0.9y=6

Thus the option 3 is the correct option.

<h3>What is allegation?</h3>

Allegation is a method to find the ratio in which two or more indignant are mixed to produce a mixture or solution.

Given information-

A scientist needs 10 L of a solution that is 60% acid.

The percentage of two acid solution are 50% and 90%.

Variable<em> x</em><em> </em>represent the number of liters of the 50% solution.

Variable<em> y </em>represent the number of liters of the 90% solution.

Quantity of acid from 50% solution is 0.5x liters, and quantity of acid from 90% solution is 0.9x liters.

As the scientist needs 10 L of a solution that is 60% acid. Therefore the quantity of acid in 60 percent acid solution is,

a=10\times\dfrac{60}{100} \\a=6

Thus 6 liters of acid required by the scientist. As to get the 6 liters of acid from 50% and 90 percent solution, we need to add the amount of acid in these solutions.Thus,

0.5x+0.9y=6

This is the required equation.

Hence the equation represents the total liters of acid that are needed is,

0.5x+0.9y=6

Thus the option 3 is the correct option.

Learn more about the mixture and allegation  here;

brainly.com/question/24372098

8 0
2 years ago
Explain how you can use doubles when multiplying with 4 to find 4x8
STALIN [3.7K]
You can figure out what four times eight is by adding eight and eight(16) and doubling it (32)
8 0
3 years ago
Other questions:
  • The price of a wallet is $31.95 and the sales tax is 7.5%. What is the total cost of the wallet? Enter your answer in the box.
    14·2 answers
  • Write an equation in slope-intercept form for the line with slope 8 and y-intercept -8.
    10·1 answer
  • Alex is installing wooden flooring in his room. The room is rectangular in shape with length of 12 feet and width of 10 feet.
    5·1 answer
  • Lincoln wants to mix 3/8 of a liter of red paint with 7/8 of a liter of blue paint to make purple paint. How many liters of purp
    11·1 answer
  • best rentals charges a daily fee plus a mileage fee for renting its cars. barney was charged $159 for 3 days and 300 miles, whil
    8·1 answer
  • PLZ ANSWER THIS FOR THE BABY DUCKS
    14·1 answer
  • Select the step in the solution that FIRST shows an error.
    12·2 answers
  • 9 hundred equals how many tens
    5·1 answer
  • Which answer best describes the complex zeros of the polynomial function? f(x)=x3+x2+10x+10
    12·1 answer
  • Downtime refers to the time duration that the service is unavailable, how much cumulative downtime per year will an sla percenta
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!