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3 years ago

Find the slope of the line that passes through the points (2,-5) and (7,1)

1 answer:

4 0

Slope is y2-y1/x2-x1
(2,-5) can be your x1 and y1
(7,1) can be your x2 and y2
1-(-5)/7-2
1+5/5
6/5
The slope of the line is 6/5
Hope I helped!

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2 years ago

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3 years ago

Hester sells televisions. She earns a fixed amount for each television and an additional $ 15 if the buyer gets an extended war

tiny-mole [99]

Answer:

$y =mx +bx$

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For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:

$1200 = 15*16 +16b$

and solving for b we got:

$b= \frac{1200-15*16}{16}= 60$

And then we can conclude that she earns 60 for each TV

Step-by-step explanation:

For this case we can set a linear model like this:

$y =mx +bx$

Where y is the total amount earned, m the amount for each extended warranty and b the fixed cost and x the total amount of TVs

For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:

$1200 = 15*16 +16b$

and solving for b we got:

$b= \frac{1200-15*16}{16}= 60$

And then we can conclude that she earns 60 for each TV

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2 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

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2 years ago