Answer:
Apply sine theorem:
1.
c/sinC = a/sinA
=> sinC = sinA x (c/a) = sin70 x 28/24 = 1.096 => Invalid ( 1.096 > 1)
=> C is undefined
=> B is undefined
2.
c/sinC = b/sinB
=> sinB = sinc x (b/c) = sin40 x 34/33 = 0.662
=> B = arcsin(0.662) = 41.47 deg
3.
c/sinC = b/sinB
=> sinB = sinC x (b/c) = sin29 x 26/6 = 2.101 => Invalid ( 2.101 > 1)
=> B is undefined
=> A is undefined
4.
c/sinC = a/sinA
=> sinC = sinA x (c/a) = sin28 x 20/16 = 0.587
=> C = arcsin(0.587) = 35.93 deg
Hope this helps!
:)
The answer you are looking for here is 22.
If we were to imagine a single point (1,1) which is in quadrant 1, and we rotate it 90o then we get a negative x. Another 90o then both x and y is negative. another 90 (270) and we get a negative y.
thus:
(e)(f)(g)(h) = (-1,-1)(-1,-2)(-2,-1)(-2,-2)
Answer:
Answer is the last one ,(A)
Step-by-step explanation:
Step 1: Add -67y to both sides.
aq+qy+−67y=67y+93+−67y
aq+qy−67y=93
Step 2: Add -aq to both sides.
aq+qy−67y+−aq=93−aq
qy−67y=−aq+93
Step 3: Factor out variable y.
y(q−67)=−aq+93
Step 4: Divide both sides by q-67.
y(q−67)/q−67=. -aq+93/q−67
y=−aq+93/q−67
Answer:
y=−aq+93/q−67