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olga nikolaevna [1]
3 years ago
10

The sum of 4 consecutive multiples of 6 is 540. What is the greatest of these numbers?

Mathematics
1 answer:
pychu [463]3 years ago
4 0

Answer:

144

Step-by-step explanation:

First: 6x

Second: 6x+6

Third: 6x+12

Fourth: 6x+18

- Since they're multiples of 6

6x+6x+6+6x+12+6x+18=540

24x+36=540\\

Subract 36 from each side give us...

24x=504\\x=21

21(6)+18=144

Hope this helped! Please mark brainliest :)

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4. Name the first five terms of the arithmetic sequence. a1 = -35, d=4​
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Answer:

Step-by-step explanation:

We first have to write the equation for the sequence, then finding the first five terms will be easy. Follow the formatting:

a_n=a_1+d(n-1) and we are given enough info to fill in:

a_n=-35+4(n-1) and

a_n=-35+4n-4 and

a_n=-39+4n or in linear format:

a_n=4n-39 where n is the position of the number in the sequence. We already know the first term is -35.

The second term:

a_2=4(2)-39 so

a_2=8-39 and

a_2=-31

The third term:

a_3=4(3)-39 and

a_3=12-39 so

a_3=-27 and we could go on like this forever, but the nice thing about this is when we know the difference all we have to do is add it to each number to get to the next number.

That means that the fourth term will be -27 + 4 which is -23.

The fifth term then will be -23 + 4 which is -19. You can check yourself by filling in a 5 for n in the equation and solving:

a_5=4(5)-39 and

a_5=20-39 so

a_5=-19

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