3 years ago

The sum of 4 consecutive multiples of 6 is 540. What is the greatest of these numbers?

Mathematics

1 answer:

pychu [463]3 years ago

4 0

Answer:

144

Step-by-step explanation:

First: 6x

Second: 6x+6

Third: 6x+12

Fourth: 6x+18

- Since they're multiples of 6

$6x+6x+6+6x+12+6x+18=540$

$24x+36=540\\$

Subract 36 from each side give us...

$24x=504\\x=21$

$21(6)+18=144$

Hope this helped! Please mark brainliest :)

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