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Vesna [10]
3 years ago
12

What is 8244 estimated

Mathematics
2 answers:
serg [7]3 years ago
8 0


8244 to the nearest thousand is 8000


lakkis [162]3 years ago
4 0

Answer:

8,000.

Step-by-step explanation:

We are asked to estimate 8,244.

Since we have been not given the place to which we need to estimate, so we will estimate our given number to different place values.

Estimated to nearest tenth:

Since ones digit is less than 5, so we will round down our answer to nearest tens as:

8,244\approx 8,240

Estimated to nearest hundred:

Since tens digit is less than 5, so we will round down our answer to nearest hundreds as:

8,244\approx 8,200

Estimated to nearest thousand:

Since hundreds digit is less than 5, so we will round down our answer to nearest thousands as:

8,244\approx 8,000

Therefore, our estimated number would be 8,000.

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In 2013, the moose population in a park was measured to be 5,100. By 2018, the population was measured again to be 5,200. If the
natka813 [3]

Answer:

P(t) = 5100e^{0.0039t}

Step-by-step explanation:

The exponential model for the population in t years after 2013 is given by:

P(t) = P(0)e^{rt}

In which P(0) is the population in 2013 and r is the growth rate.

In 2013, the moose population in a park was measured to be 5,100

This means that P(0) = 5100

So

P(t) = 5100e^{rt}

By 2018, the population was measured again to be 5,200.

2018 is 2018-2013 = 5 years after 2013.

So this means that P(5) = 5200.

We use this to find r.

P(t) = 5100e^{rt}

5200 = 5100e^{5r}

e^{5r} = \frac{52}{51}

\ln{e^{5r}} = \ln{\frac{52}{51}}

5r = \ln{\frac{52}{51}}

r = \frac{\ln{\frac{52}{51}}}{5}

r = 0.0039

So the equation for the moose population is:

P(t) = 5100e^{0.0039t}

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3 years ago
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weqwewe [10]

Answer:

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