Answer:
m=4
Step-by-step explanation:
1/8=m/32
cross product
8*m=1*32
8m=32
m=32/8
m=4
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

By substitution, we have that

and

.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
Step-by-step explanation:
5x + 2 = 4x - 9
Collecting like terms
5x - 4x = -9 - 2
x = -11
The answer is 46.8
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<u>Answer:
</u>
The standard form of
is 20,00,0000
<u>Solution:
</u>
Given that
---- eqn 1
To write
in standard form,
We know that
.So
becomes
.
Now eqn 1 becomes,
----- eqn 2
We know that
, so 
Now eqn 2 becomes,

---- eqn 3
Expanding
:
Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

Now eqn 3 becomes,

= 20,00,0000
Hence the standard form of
is 20,00,0000