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Gelneren [198K]
3 years ago
14

A certain field is a rectangle with a perimeter of 934 feet. The length is 153 feet more than the width. Find the width and leng

th of the rectangular field.
Mathematics
1 answer:
arsen [322]3 years ago
7 0
Answer :

Perimeter = 2(l + b)

So, let breadth be = x
let length be. = 153 + x

So, P = 2(l + b)
= 2(153 + x + (x)

2x + 306 + 2x = 934
4x = 628
x = 628/4
x = 157

B = 157
L = 310
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what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube
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<u>Answer: </u>

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<u>Solution: </u>

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To write\frac{6 \times 10^{2}}{3 \times 10^{-5}} in standard form,

We know that \bold{\frac{1}{a^{-m}} = a^{m}} .So \frac{1}{10^{-5}}  becomes 10^{5}.

Now eqn 1 becomes,

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