What are the x intercepts of y=x^2-x-12

Last year, 45% of business owners gave a holiday gift to their employees. A survey of business owners conducted this year indica

natka813 [3]

Answer:

a)x₁ = 24 business owners plan to provide a gift this year

b) p-value = 0,0017

c)p-value < α we have to eject H₀ And support the claim that the proportion of business owners providing gifts has decrease

Step-by-step explanation:

a) Sample size 80

proportion p₁ = 30 % p₁ = 0,3

Then x₁ = 80*0,3

x₁ = 24 business owners plan to provide a gift this year

b) Hypothesis Test

Null Hypothesis H₀ p₁ = 0,45

Alternative Hypothesis Hₐ p₁ < 0,45

p₁ = 0,3 then q₁ = 1 - 0,3 q₁ = 0,7

z(s) = ( p₁ - 0,45 )/ √p₁* q₁ / n

z(s) = - 0,15 / √0,002625

z(s) = - 0,15 / 0,05123

z(s) = - 2,9279

b)From z-table we find p-value = 0,0017

c) If α = 0,05 ( significance level ) as

p-value < α we have to eject H₀ And support the claim that the proportion of business owners providing gifts has decrease

6 0

3 years ago

Write a word problem using division plz help me

Scrat [10]

Mark has 5 friends over and he baked 25 cookies. How many cookies does each friend get?

8 0

3 years ago

Read 2 more answers

$580, 2%, 6 months Simple interest

Helen [10]

Answer:

$580 2% a month for 6 months equals $649.60

Step-by-step explanation:

$580*0.02=$11.6

$11.6*6=$69.6

$580+$69.6=

$649.6

0.02 equals 2 percent as a decimal

6 0

3 years ago

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0

3 years ago

Which transformation is happening in the image below

s2008m [1.1K]

Answer:

B.) Reflection over y=-3

Step-by-step explanation:

8 0

3 years ago