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3 years ago

Can someone please help me with this I’ll give brainliest

Mathematics

1 answer:

liq [111]3 years ago

5 0

Answer:

The solutions are -2 and 3

Step-by-step explanation:

You can find the solutions to a quadratic by looking at where the line/arch intersects the x-axis. In this case, the quadratic intersected it at -2,0 and 3,0.

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One stack has 6 cups, and its height is 15 cm. The other one has 12 cups, and its height is 23 cm. How many cups are needed for

Ronch [10]

Answer:

Given

Number of stacks = 2

Stack 1 = 6 cups; h1 = 15cm

Stack 2 = 12 cups; h2 = 23cm

Let's first find the average:

With an average of 4/3, to obtain the number of cups needed to obtain a height of 50m, we have:

50 / (4/3)

= 50 * 3/4

= 150/4

= 37.5

From the answer, we can see that the number of cups is not really proportional to the height of the stack, because the average of stack one and stack 2 are different.

Step-by-step explanation:

7 0

3 years ago

Help please I need the answers

Cerrena [4.2K]

Answer:

Step-by-step explanation:

6 0

3 years ago

If you left $25.00 on your table for a $21.50 meal, what was the percent of the tip?

Nesterboy [21]

Answer: 3.5% with a 3.50 Tip

Reason: 25.00 - 21.50 = 3.50

4 0

3 years ago

Read 2 more answers

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Visualize the following procedure: Tear in half a square piece of paper with an area of one square unit. Then tear it in half ag

Nadusha1986 [10]

Answer:

$Area = \frac{1}{16}$ square units

Step-by-step explanation:

To predict the area of the piece of paper after 5 tears we can use a geometric sequence.

Each time a piece is torn, half of the previous area is lost. If the area of the first piece is 1 square unit then:

$a_1 = 1\\\\r = \frac{1}{2}\\\\a_2 = 1 *\frac{1}{2}\\\\a_2 = \frac{1}{2}\\\\a_n = 1(\frac{1}{2})^{n-1}\\\\a_5 = 1(\frac{1}{2})^{5-1}$

$a_5 = \frac{1}{16}$ square units

4 0

4 years ago

Read 2 more answers