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elena-14-01-66 [18.8K]
3 years ago
11

Can someone please help me with this I’ll give brainliest

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

The solutions are -2 and 3

Step-by-step explanation:

You can find the solutions to a quadratic by looking at where the line/arch intersects the x-axis. In this case, the quadratic intersected it at -2,0 and 3,0.

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What is (-10/-25)5+24x85=
Marina86 [1]

Answer:

2042

Step-by-step explanation:

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3 years ago
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Write an equation of a line in slope-intercept form that passes through the point (8, 9) and has a slope of 3.
Komok [63]

Answer:

y=3x-15

Step-by-step explanation:

y-y1=m(x-x1)

y-9=3(x-8)

y=3x-24+9

y=3x-15

6 0
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The zoo feeds the tortoise, rhinoceros, and zebra a total of 23 pounds of vegetables a day. How many pounds does the zoo feed th
vekshin1

If I understand your question correctly, you want to know how many pounds of vegetables the zoo feeds the animals a month if its a 30 day month?

In that case it would be 23 pounds times 30 days which is 690 pounds of vegetables. SO the zoo feeds the animals 690 pounds of vegetables to the animals each month.

Is that what your asking for?

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3 years ago
Write a formula for perimeter and area of a circle<br> Thank you !
Ratling [72]

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<em>The area of a circle is πr2 and the perimeter (circumference) is 2πr</em>

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3 years ago
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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
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