Answer:
36.5cm²
Step-by-step explanation:
Area of quarter circle=8²/4=64
/4=16
cm²
Area of square+Area of shaded region =2(16)=32
=100.5cm²
Area of square=8²=64cm²
Area of shaded region=100.5cm²-64cm²=36.5cm²
Therefore, the area of the shaded region is 36.5cm².
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
Answer:
f(x)^-1 =
Step-by-step explanation:
f(x) = (4x - 3) / 7
y = (4x - 3) / 7
x = (4y - 3) / 7
x / 7 = 4y - 3
x/7 + 3 = 4y
y =
