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Anni [7]
3 years ago
10

A company has 2 photocopy machines. The probability that machine A will breakdown on a given day is 2%. The probability that mac

hine B will break down is 2.5%. What is the probability that neither machines will break down on a given day? Give your answer in percent.
Mathematics
2 answers:
pickupchik [31]3 years ago
8 0
Answer: 95.55%

--------------------------------

Work Shown:

A = event that copier A breaks down
B = event that copier B breaks down

P(A) = probability that copier A breaks down
P(A) = 2% = 0.02

P(B) = probability that copier B breaks down
P(B) = 2.5% = 0.025

P(neither break down) = (1-P(A))*(1-P(B))
P(neither break down) = (1-0.02)*(1-0.025)
P(neither break down) = 0.9555
P(neither break down) = 95.55%
kolbaska11 [484]3 years ago
4 0
the answer is 95.55%
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3 years ago
a positive number is 5 times less than another positive number. Six times the lesser number plus 3 times the greater is 3. Find
IgorLugansk [536]
<h2>Greetings!</h2>

Answer:

One number is \frac{5}{7} and the other number is \frac{1}{7}

Step-by-step explanation:

Let x be the smaller number and y be the bigger number.

x = x

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6x + 3y = 3

6x + (3 * 5x) = 3

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(÷3)

2x + 5x = 1

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x = \frac{1}{7}

6x + 3y = 3

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3y = 3 - \frac{6}{7}

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Divide both sides by 3 to get 1y:

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So one number is \frac{5}{7} and the other number is \frac{1}{7}


<h2>Hope this helps!</h2>
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Answer:

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Step-by-step explanation:

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Let the radius of the bottle be r cm.

∴ π × r^{2} × h = 211 ; (π = 3.15)

⇒ r^{2} × 24.885 = 211

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2. What inference can you make by comparing the measures

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