A company has 2 photocopy machines. The probability that machine A will breakdown on a given day is 2%. The probability that mac
hine B will break down is 2.5%. What is the probability that neither machines will break down on a given day? Give your answer in percent.
2 answers:
Answer: 95.55%
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Work Shown:
A = event that copier A breaks down
B = event that copier B breaks down
P(A) = probability that copier A breaks down
P(A) = 2% = 0.02
P(B) = probability that copier B breaks down
P(B) = 2.5% = 0.025
P(neither break down) = (1-P(A))*(1-P(B))
P(neither break down) = (1-0.02)*(1-0.025)
P(neither break down) = 0.9555
P(neither break down) = 95.55%
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Step-by-step explanation:
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