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Anni [7]
3 years ago
10

A company has 2 photocopy machines. The probability that machine A will breakdown on a given day is 2%. The probability that mac

hine B will break down is 2.5%. What is the probability that neither machines will break down on a given day? Give your answer in percent.
Mathematics
2 answers:
pickupchik [31]3 years ago
8 0
Answer: 95.55%

--------------------------------

Work Shown:

A = event that copier A breaks down
B = event that copier B breaks down

P(A) = probability that copier A breaks down
P(A) = 2% = 0.02

P(B) = probability that copier B breaks down
P(B) = 2.5% = 0.025

P(neither break down) = (1-P(A))*(1-P(B))
P(neither break down) = (1-0.02)*(1-0.025)
P(neither break down) = 0.9555
P(neither break down) = 95.55%
kolbaska11 [484]3 years ago
4 0
the answer is 95.55%
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Ok, so probablility of not drawing blue

total possible is 8+6+12+10=36

8 are blue so the total of not blue is 36-8=28

<span>so 28 out of 36=28/36=7/9 </span>
<span>the asnwer is 7/9 or C</span>
7 0
3 years ago
Eggs are boxed in a crate. Each crate has 485 eggs. How many eggs are there in 525 ?
zzz [600]

Answer:

254,625 eggs

Step-by-step explanation:

Multiply 485 eggs by 525 crates

7 0
3 years ago
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A business owner needs to hire a cleaning service for the office. The cleaning company charges $250 for 5 rooms. The office has
joja [24]

Answer:

Step 2 should have been $50 × 12 rooms = $600.

Step-by-step explanation:

In step 2, there is no need for him to add $250 when the 12 rooms will already cover the cost of the entire job. The cost of 5 rooms was just a reference for us to use to find the cost per room.

50 * 12 = $600

Best of Luck!

8 0
3 years ago
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A simple random sample of 85 analog circuits is obtained at random from an ongoing production process in which 21% of all circui
Ulleksa [173]

Answer:

63.81% probability that between 14 and 20 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 85, p = 0.21.

So

E(X) = np = 85*0.21 = 17.85

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{85*0.21*0.79} = 3.7552

P ( 14 ≤ X ≤ 20 )

Using continuity correction, this is P(14 - 0.5 \leq X \leq 20 + 0.5) = P(13.5 \leq X \leq 20.5), which is the pvalue of Z when X = 20.5 subtracted by the pvalue of Z when X = 13.5. So

X  = 20.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{20.5 - 17.85}{3.7552}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 13.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{13.5 - 17.85}{3.7552}

Z = -1.16

Z = -1.16 has a pvalue of 0.1230

0.7611 - 0.1230 = 0.6381

63.81% probability that between 14 and 20 circuits in the sample are defective.

6 0
3 years ago
Will give brainlest<br> g(-5)=?
bekas [8.4K]

Answer:

-6

Step-by-step explanation:

g(-5) is the value of function g at x value -5

the graph shows the point (-5,-6), so g(-5)=-6

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