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koban [17]
3 years ago
6

In the chart below is the depth of a submarine in the ocean over several

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

B. Submarine travelled 50 ft.

A. Submarine is descending (toward bottom)

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\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}

Or, if you mean (r+3Q)/h=t:

\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}

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