2. A bag contains 25 paise coins and 50 paise Coins. The number of 25 paise coins is 6 times that of so paise Coins The total va
1 answer:
<h2>~<u>Solution</u> :-</h2>
Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.
- Hence, we can see that, here, we have been given the linear equation be;
Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .
Hence,
- Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;
- Hence, the number of 25 paise coins will be <u>12</u>.
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Answer:
Range = 2460 dollars, Variance = 516414.6 , Standard deviation = 718.6199 dollars . There are two outliers and they are likely to have much of an effect on the measures of variation.
Step-by-step explanation:
The smallest value in the sample data is min = 50 dollars and the largest value is max = 2500 dollars, therefore, the range is Range = max - min = 2500 - 40 = 2460 dollars. On the other hand, the formula to compute the sample variance is where
is the sample mean, n is the sample size and the
are the sample values. In this case the sample variance is
= 516414.6
, the sample standard deviation is defined as the squared root of the sample variance, so, the sample standard deviation is s = 718.6199 dollars. There are two outliers because 1750 dollars and 2500 dollars are very different compared to the other values, these two numbers are very large and they are likely to have much of an effect on the measures of variation because these measures are sensible to outliers, they are no robust measures.