1 markers cost $7.04 Which equation would help determine the cost of 7 markers!

Lin and Diego both ran for 10 seconds, each at their own constant speed. Lin ran 40 meters and Diego ran 55 meters. 1. Who was m

Igoryamba

Answer:

Diego ran faster

Step-by-step explanation:

In the ten seconds, Diego ran 15 meters faster than Lin.

55 - 40 = 15

5 0

3 years ago

A bicyclist rides 16 miles in 144 minutes. If she continues at this speed, how long will it take her to travel 36 miles?

zepelin [54]

The correct answer is possibly 324

5 0

4 years ago

Read 2 more answers

(-7)^2 Help Also what's your zodiac sign?

soldier1979 [14.2K]

Answer: 49

and im a taurus

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A car is manufactured for a cost of $12,500. The dealership purchases the car and puts a markup of 67% on the car. The car is pu

Naya [18.7K]

<h3>Answer:</h3>

$12,500 — dealer cost
$20,875 — owner cost
$5385.75 — owner's selling price

<h3>Step-by-step explanation:</h3>

The problem statement is missing a lot of information, so we'll make some assumptions:

the cost of manufacture is the dealer's cost
the markup percentage uses the dealer's cost as a base
the car is purchased for the marked price in each case.

1. The dealer's cost is the cost of manufacture: $12,500.

2. The marked-up price is

$12,500 + 0.67×12,500 = $20,875.

3. The book value after 8 years is

$20,875 - 0.57×20,875 = $8976.25

So, the Craigslist price is

0.60×$8976.25 = $5385.75

4 0

3 years ago

The mean hourly wage for employees in industries is currently $24.57. Suppose we take a sample of employees from the manufacturi

Mashutka [201]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = $24.57

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $24.57

(b) The P-value of the test statistics is 0.1212.

(c) We conclude that the population mean hourly wage in the manufacturing industry equals the population mean hourly wage in the U.S industries using P-value approach.

(d) We conclude that the population mean hourly wage in the manufacturing industry equals the population mean hourly wage in the U.S industries using critical value approach.

Step-by-step explanation:

We are given that a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the U.S industries.

Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population standard deviation of $2.40 per hour.

Let $\mu$ = population mean hourly wage in the manufacturing industry.

(a) Null Hypothesis, $H_0$ : $\mu$ = $24.57 {means that the population mean hourly wage in the manufacturing industry equals the population mean hourly wage in the U.S industries}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $24.57 {means that the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the U.S industries}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean wage in the manufacturing industry = $23.89/hr

σ = population standard deviation = $2.40/hr

n = sample of employees from the manufacturing industry = 30

So, the test statistics = $\frac{23.89-24.57}{\frac{2.40}{\sqrt{30} } }$

= -1.55

The value of z test statistics is -1.55.

(b) Now, the P-value of the test statistics is given by;

P-value = P(Z < -1.55) = 1 - P(Z $\leq$ 1.55)

= 1 - 0.9394 = 0.0606

For two-tailed test P-value is calculated as = 0.0606 $\times$ 2 = 0.1212

Since, the P-value of the test statistics is higher than the level of significance as 0.1212 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population mean hourly wage in the manufacturing industry equals the population mean hourly wage in the U.S industries.

(d) Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population mean hourly wage in the manufacturing industry equals the population mean hourly wage in the U.S industries.

6 0

3 years ago