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algol [13]
3 years ago
8

PLEASE HELP ME

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0
In square based pyramid
Length of base (a)=6cm
Slant height (l)=4 cm
Now,
LSA=2al
= 2*6*4
=48cm^2
Paha777 [63]3 years ago
4 0

Answer:

Surrounding area of pyramid = area of a side face multiplied by 4

Step-by-step explanation:

The area of a side face is the area of the triangle:

\frac{1}{2} *6*4 = 12

So the perimeter of the pyramid is:

12×4=48

Explanation: because the side faces have the same area.

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lozanna [386]

Answer:C

Step-by-step explanation:

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8 0
3 years ago
The perimeter of an equilateral triangle is 38 centimeters. Find the length of an
Leokris [45]

Answer:

11.0 cm

P=38 cm

38/3=12.67cm length of one side

Base of triangle = 12.67/2 =6.34 cm

Use formula a^2+b^2=c^2

6.34^2+x^2=12.67^2\\\\=11.0 cm

x = altitude of triangle

8 0
2 years ago
True False: Complementary angles sometimes fom straight angles
wel

Answer:

False

Step-by-step explanation:

Complementary angles form a right angle (L shape) and have a sum of 90 degrees. Supplementary angles form a straight line and have a sum of 180 degrees.

6 0
3 years ago
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mixas84 [53]

Answer:

B.) teacher

Step-by-step explanation:

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5 0
3 years ago
Find t given that these vectors are perpendicular
stira [4]

(a) If <em>p</em> and <em>q</em> are perpendicular (or orthogonal), then their dot product is 0:

\mathbf p^\top\mathbf q = \begin{pmatrix}3&t\end{pmatrix}\begin{pmatrix}-2\\1\end{pmatrix} = 3\times(-2)+t\times1 = t-6 = 0 \implies \boxed{t=6}

(b) and (c) can be answered in the same way.

(b)

\begin{pmatrix}t&t+2\end{pmatrix}\begin{pmatrix}3\\-4\end{pmatrix} = 3t-4(t+2) = -t-8 = 0 \implies \boxed{t=-8}

(c)

\begin{pmatrix}t&t+2\end{pmatrix}\begin{pmatrix}2-3t\\t\end{pmatrix} = t(2-3t)+(t+2)t = 4t-2t^2 = 2t(2-t)=0 \implies \boxed{t=0\text{ or }t=2}

3 0
3 years ago
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