All categories

4 years ago

How can you turn 4512 into a mixed number?

Mathematics

2 answers:

arlik [135]4 years ago

4 0

Yes, you would get 3 3/4.

Anettt [7]4 years ago

3 0

You would get 3 3/4 like what the other person said

You might be interested in

20 Points! please Help Thanks! In Return brainliest and special thanks

sdas [7]

3. m=43
4: m=-46
5:m=-44
6:=-16

3 0

3 years ago

sharon has $24 and begins saving $8 each week toward buying new clothes Wes has $36 and begins saving $5 each week is there a we

tatuchka [14]

Answer:

in 4 weeks

Step-by-step explanation:

24+8(4)=56

36×5(4)=56

in 4 weeks they both will have $56

4 0

3 years ago

Read 2 more answers

Determine the values of the constants r and s such that i(x, y) = x rys is an integrating factor for the given differential equa

garri49 [273]

$\underbrace{y(7xy^2+6)}_{M(x,y)}\,\mathrm dx+\underbrace{x(xy^2-1)}_{N(x,y)}\,\mathrm dy=0$

For the ODE to be exact, we require that $M_y=N_x$ , which we'll verify is not the case here.

$M_y=21xy^2+6$
$N_x=2xy^2-1$

So we distribute an integrating factor $i(x,y)$ across both sides of the ODE to get

$iM\,\mathrm dx+iN\,\mathrm dy=0$

Now for the ODE to be exact, we require $(iM)_y=(iN)_x$ , which in turn means

$i_yM+iM_y=i_xN+iN_x\implies i(M_y-N_x)=i_xN-i_yM$

Suppose $i(x,y)=x^ry^s$ . Then substituting everything into the PDE above, we have

$x^ry^s(19xy^2+7)=rx^{r-1}y^s(x^2y^2-x)-sx^ry^{s-1}(7xy^3+6y)$
$19x^{r+1}y^{s+2}+7x^ry^s=rx^{r+1}y^{s+2}-rx^ry^s-7sx^{r+1}y^{s+2}-6sx^ry^s$
$19x^{r+1}y^{s+2}+7x^ry^s=(r-7s)x^{r+1}y^{s+2}-(r+6s)x^ry^s$
$\implies\begin{cases}r-7s=19\\r+6s=-7\end{cases}\implies r=5,s=-2$

so that our integrating factor is $i(x,y)=x^5y^{-2}$ . Our ODE is now

$(7x^6y+6x^5y^{-1})\,\mathrm dx+(x^7-x^6y^{-2})\,\mathrm dy=0$

Renaming $M(x,y)$ and $N(x,y)$ to our current coefficients, we end up with partial derivatives

$M_y=7x^6-6x^5y^{-2}$
$N_x=7x^6-6x^5y^{-2}$

as desired, so our new ODE is indeed exact.

Next, we're looking for a solution of the form $\Psi(x,y)=C$ . By the chain rule, we have

$\Psi_x=7x^6y+6x^5y^{-1}\implies\Psi=x^7y+x^6y^{-1}+f(y)$

Differentiating with respect to $y$ yields

$\Psi_y=x^7-x^6y^{-2}=x^7-x^6y^{-2}+\dfrac{\mathrm df}{\mathrm dy}$
$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

Thus the solution to the ODE is

$\Psi(x,y)=x^7y+x^6y^{-1}=C$

4 0

3 years ago

This is super hard i needd help

natta225 [31]

Answer:

2587mm^3 approx!

Step-by-step explanation:

first you divide the nut into 6 part(in triangle now, by joining centre to each edge)

let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height

i.e, 1/2×13×15=97.5(mm^2)

now when we consider depth of that traingular part,we will get volume of that part as area×depth

i.e, 97.5×6=585(mm^3)

now volume of all the 6 triangular part is 585×6=3510(in mm^3)

now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately

now reqired volume will be volume of that hexagonal part minus that of circular cavity

=3510-923

=2587mm^3

✌️

5 0

3 years ago

I don’t understand this

zhuklara [117]

Answer:

i think it is the last one.

7 0

3 years ago