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Bad White [126]
2 years ago
15

A student finds the slope of the line between (14, 1) and (18, 17). She writes . What mistake did she make? She mixed up the x-

and y-values. She used y-values where she should have used x-values. She did not keep the order of the points the same in the numerator and the denominator. She should have added the values, not subtracted them.
Mathematics
2 answers:
yanalaym [24]2 years ago
7 0

Answer:

She did not keep the order of the points the same in the numerator and the denominator.

Step-by-step explanation:

IRINA_888 [86]2 years ago
4 0

Answer:

you just said the answer

You might be interested in
At what point does she lose contact with the snowball and fly off at a tangent? That is
postnew [5]

Answer:

α ≥ 48.2°

Step-by-step explanation:

The complete question is given as follows:

" A skier starts at the top of a very large frictionless snowball, with a very small initial speed, and skis straight  down the side. At what point does she lose contact with the snowball and fly off at a tangent? That is, at the  instant she loses contact with the snowball, what angle α does a radial line from the center of the snowball to  the skier make with the vertical?"

- The figure is also attached.

Solution:

- The skier has a mass (m) and the snowball’s radius (r).

- Choose the center of the snowball to be the zero of gravitational  potential. - We can look at the velocity (v) as a function of the angle (α) and find the specific α at which the skier lifts off and  departs from the snowball.

- If we ignore snow-­ski friction along with air resistance, then the one work producing force in this problem, gravity,  is conservative. Therefore the skier’s total mechanical energy at any angle α is the same as her total mechanical  energy at the top of the snowball.

- Hence, From conservation of energy we have:

                       KE (α) + PE(α) = KE(α = 0) + PE(α = 0)

                       0.2*m*v(α)^2 + m*g*r*cos(α) = 0.5*m*[ v(α = 0)]^2 + m*g*r

                       0.2*m*v(α)^2 + m*g*r*cos(α) ≈ m*g*r

                        m*v(α)^2 / r = 2*m*g( 1 - cos(α) )

- The centripetal force (due to gravity) will be mgcosα, so the skier will remain on the snowball as long as gravity  can hold her to that path, i.e. as long as:

                         m*g*cos(α) ≥ 2*m*g( 1 - cos(α) )

- Any radial gravitational force beyond what is necessary for the circular motion will be balanced by the normal  force—or else the skier will sink into the snowball.

- The expression for α_lift becomes:

                            3*cos(α) ≥ 2

                            α ≥ arc cos ( 2/3) ≥ 48.2°

4 0
2 years ago
(2.7 x 10 to the power of 4) (3.5 x 10 to the power of 3)
AveGali [126]

Answer:

Step-by-step explanation:

(2.7)(10)

=27

27^4=531441

-------------------------------

(3.5)(10)

=35

35^3=42875

7 0
3 years ago
Help me please!!°-°​
masya89 [10]
It was complicated but I did it

4 0
3 years ago
Write an equation of the line through (6,-5) having slope 0. Give the answer in standard form.
allsm [11]

0x + 1y = -5 is the standard form of equation

<em><u>Solution:</u></em>

Given that we have to write the equation of line passing thorugh (6, -5) and has slope 0

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ---------- eqn 1

Where, "m" is the slope of line and "c" is the y - intercept

Given that, m = 0

Given point is (6, -5)

<em><u>To find the y - intercept:</u></em>

<em><u>Substitute (x, y) = (6, -5) and m = 0 in eqn 1</u></em>

-5 = 0(6) + c

c = -5

<em><u>Substitute c = -5 and m = 0 in eqn 1</u></em>

y = 0x + (-5)

y = -5

<em><u>The standard form of equation is given as:</u></em>

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

y = -5

0x + 1y = -5 is the standard form of equation

8 0
2 years ago
If f(x) varies directly with x and f(x)=40 when x=8, find the value of f(x) when x=2.
melamori03 [73]

f(x)=40

x=8

so if x=2 it would be 40/8 which is 5

6 0
2 years ago
Read 2 more answers
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