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MaRussiya [10]
4 years ago
5

1. Find the equation of a line that passes through the point (4,1) and is perpendicular to the

Mathematics
1 answer:
slava [35]4 years ago
7 0

Answer:

  x - 4y = 0 . . . in standard form

  y = (1/4)x . . . in slope-intercept form

Step-by-step explanation:

The slope of the given line is ...

  m = (y2 -y1)/(x2 -x1) = (9 -(-7))/(-1 -3) = 16/-4 = -4

The slope of the perpendicular line is the negative reciprocal of this:

  desired slope = -1/m = -1/-4 = 1/4

This can be used in the point-slope form of the equation of a line:

  y -h = m(x -k) . . . . . line with slope m through point (h, k)

Your perpendicular line has a slope of 1/4 and goes through point (4, 1), so its equation can be written as ...

  y -1 = (1/4)(x -4)

  y = (1/4)x -1 +1

  y = (1/4)x

In standard form, this is ...

  4y = x

  x -4y = 0

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An ion channel can be in either open (O) or closed (C) states. If it is open, then it has probability 0.1 of closing in 1 micros
iragen [17]

Answer:

a)  P (COO)  = 0,135

b) P ( SISI) = 0,00015

Step-by-step explanation:

a) the probability of an ion channel in open position is 50 %   0,5

   the probability of an ion channel in close position is 50 %   0,5

probability for the following sequence of states COO

to be closed   0,5    (C)

from (C) to pass to open  0,3  (O)

and to stay O  is 0,9

Then the probability of the sequence of states COO is

P (COO)  = 0,5 * 0,3 * 0,9  

P (COO)  = 0,135

b) If people are either infected or susceptible, then

Probability of an individual infected is  0,5

Probability of an individual susceptible  is 0,5

to pass from susceptible to infected is 0,05

to pass from infected to susceptible is 0,12

then

P ( SISI) = 0,5 * 0,05*0,12*0,05

P ( SISI) = 0,00015

probability for the following sequence of states COO

4 0
3 years ago
Please help asap,the first person will get the brianlist plz,answer all of the 5 questions
almond37 [142]

Step-by-step explanation:

1:d

2:c

3:a

4c

5:b

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7 0
3 years ago
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What correlation is shown by the scatter plot?
m_a_m_a [10]
Linear correlation.
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3 years ago
Which of the following are solutions to x-1 = 5x + 2 ? Check all that apply.
Ad libitum [116K]

Answer:

The answer is-3/4

Step-by-step explanation:

#Hope it helps uh.....

5 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
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