1. Find the equation of a line that passes through the point (4,1) and is perpendicular to the
1 answer:
Answer:
x - 4y = 0 . . . in standard form
y = (1/4)x . . . in slope-intercept form
Step-by-step explanation:
The slope of the given line is ...
m = (y2 -y1)/(x2 -x1) = (9 -(-7))/(-1 -3) = 16/-4 = -4
The slope of the perpendicular line is the negative reciprocal of this:
desired slope = -1/m = -1/-4 = 1/4
This can be used in the point-slope form of the equation of a line:
y -h = m(x -k) . . . . . line with slope m through point (h, k)
Your perpendicular line has a slope of 1/4 and goes through point (4, 1), so its equation can be written as ...
y -1 = (1/4)(x -4)
y = (1/4)x -1 +1
y = (1/4)x
In standard form, this is ...
4y = x
x -4y = 0
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Answer:
sin -115° = -0.91
Step-by-step explanation:
Point A is (cos 115°, sin 115°). Since cos 115° = -0.42 and sin 115° ≈ 0.91, it means that the coordinates at point A is (-0.42, 0.91).
As for point B which was revolved around -115°,
the coordinates will be similar to point A but you just have to change the negative.
B(cos -115°, sin -115°) = B(0.42, -0.91)
