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Tpy6a [65]
3 years ago
12

Isaiah and his children went into a grocery store and where they sell apples for $0.50 each and peaches for $1.50 each. Isaiah h

as $15 to spend and must buy no less than 14 apples and peaches altogether. If Isaiah decided to buy 8 apples, determine the maximum number of peaches that he could buy. If there are no possible solutions, submit an empty answer.
Mathematics
2 answers:
pychu [463]3 years ago
8 0

Answer:

8x0.50=4

15-4=9

9/1.50= 6

6 peaches

erica [24]3 years ago
6 0

Answer:

Maximum of <u>6 peaches</u>, and 8 apples

Explanation:

Given that the quantity of apples and peaches must total to 14, a total cost of $15, with a cost of $0.50 each for apples and a cost of $1.50 each for peaches, we can create a system of equations to solve for each variable.

0.5a + 1.50p = 15.

a + p = 14.

There are many methods that can be used but the easiest one that works for this problem is elimination.

Start by multiplying the top equation by 2 to get rid of the decimals.

0.5 a × 2 + 1.5 p × 2 = 15 × 2.

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