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gayaneshka [121]
3 years ago
7

If p varies directly as r and p= 3.2 when r=4, find the value of p when r= 6.5​

Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

Answer:

p is equal to 8.125

Step-by-step explanation:

Direct proportion formula : Y = kx ,k is constant

p = x = 3.2

r = y = 4

4 = k * 3.2

k = 4/3.2 = 1.25

y = 1.25x

Now, substitute x = 6.5 and find y.

y = 1.25 * 6.5 = 8.125

Hence p is equal to 8.125

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Answer:

2x-5= -20

move -5 to the other side

sign changes from -5 to 5

2x-5+5= -20+5

2x= -15

divide by 2 for both sides

2x/2= -15/2

cross out 2 and 2, divide by 2 and 2 and then becomes x

x= -15/2

4 0
3 years ago
A baseball is thrown from the top of a building and falls to the ground below. The height of the baseball above the ground is ap
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Marta_Voda [28]
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7 0
3 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
There are 24 boys and 16 girls on a playground what is the ratio of boys to total number of children on the playground
Vinil7 [7]

Answer:

24:40 or 3:5

Step-by-step explanation:

24+16=40. 24:40 can be simplified to 3:5.

Hope this helped!

7 0
3 years ago
Read 2 more answers
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