Answer:
(a) 
(b) 
(c) At 4 weeks, when both will be seeing an average of 3 hours of TV.
Step-by-step explanation:
a) For the students, they start at X(0)=5 h and ΔX=-0.5 h/week.
We can write
b) For the professors, they start at X(0)=1 h and ΔX=+0.5 h/week.
We can write
c) The seew which they will be watching the same amount of hours will be the 4th week.
The amount of hours will be
Answer:
(B) 39°
Step-by-step explanation:
30° + 24° + (3x -9°) = 180°
3x = 180° - 30° - 24° + 9°
3x = 117°|:3
x = 39°
There are 3,300 different ways to select the committee.
First, we need to determine the total number of ways the 6 members can be selected.
For the chair and vice chair, it would be 5 x 4 = 20, but then that has to be divided by 2. (Because the order doesn't matter)
20 / 2 = 10
For the rest, it would be 11 x 10 x 9 x 8 = 7920, but again divide it by 4! because the order doesn't matter.
7920 / 24 = 330
To find the total ways for both, multiply 10 by 330 to get 3300.
Answer:
Step-by-step explanation:
The answer is 7 first take away the last number don’t throw it away you still need it but just to make it easier then you do 8-3 which is 5 so then bring the last number back and you add 2 which gives you 7 as your answer
Multiples : these are what we get after multiplying a number by an integer (not a decimal or fraction)
Example : 6 * 1 = 6......6 * 2 = 12.....6 * 3 = 18......so 6,12, and 18 are multiples of 6.
factors : these are what we multiply by to get a number
Example : 1 * 6 = 6.....so 1 and 6 are factors of 6....2 * 3 = 6 ...so 2 and 3 are also factors of 6
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problem 1 : Look at ur clues...each number is less then or equal to 12....this right here eliminates D because of the 15. The greatest common factor of the 2 numbers is 2....and this eliminates B because if it has a factor of 2, it has to be an even number. So that leaves us with :
A. 6 and 10
C. 10 and 12
last clue....they have a least common multiple of 60...this means that ur 2 numbers cant have any other common multiples until 60.
6 * 10......both are multiples of 60...however, they are also both multiples of 30...so 60 is not the least common multiple of 6 and 10, it is 30.
Therefore, ur answer is C. 10 and 12....with the LCM of 60, LCF of 2 and < or = to 12
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problem 2 : GCF (greatest common factor) of 42 and 84
factors of 42 : 1,2,3,6,7,14,21,42
factors of 84 : 1,2,3,4,6,7,12,14,21,28,42,84
therefore, the GCF of these 2 numbers is 42
