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2 years ago

A line that includes the point (0, -2) has a slope of -3. What is its equation in slope-intercept form?

Mathematics

1 answer:

denpristay [2]2 years ago

5 0

Answer:

$y=-3x-2$

Step-by-step explanation:

Equation of straight line in slope intercept form is given as

$y=mx+b$ -------- (1)

Here $m=-3$ and $(x_1, y_1)=(0, -2)$

$y-y_1 = m(x-x_1) \\ y+2 = - 3(x-0) \\ y =-3x-2$ ----------- (2)

Comparing (1) and (2)

m=-3 and b=-2

Equation (2) is equation of straight line with slope -3 and y-intercept -2 in slope intercept form

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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IceJOKER [234]

Answer:

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Step-by-step explanation:

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2 years ago

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In triangle ABC, a = 9, c = 5, and B = 120°. Find b2.

anygoal [31]

Answer:

(D) $b^2=151$

Step-by-step explanation:

Given: In triangle ABC, a=9, c=5 and ∠B=120°.

To find: The value of $b^2$ .

solution: It is given that In triangle ABC, a=9, c=5 and ∠B=120°.

Now, using the law of cosines, we get

$b^2=a^2+c^2-2(a)(c)cosB$

Substituting the given values, we get

$b^2=9^2+5^2-2(9)(5)cosB$

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which is the required value of $b^2$ .

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snow_tiger [21]

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