Answer:
x ≤ 2
Step-by-step explanation:
We are given the inequality:

First, get rid of the denominator by multiplying both sides by 2:

Add both sides by 6 then subtract both sides by x:

Then divide both sides by 3:

Therefore, the answer is x ≤ 2
Answer:
0.508
Step-by-step explanation:
Answer:
The original number of oranges purchased is 260
Step-by-step explanation:
Let the original number of oranges purchased be x
We are given that The number of oranges a grocery store bought this year was 15% more than the number of oranges bought last year.
So, Oranges bought this year = 
We are given that This year the store bought 299 oranges.
So, 

x=260
Hence the original number of oranges purchased is 260
Answer:
A=72
Step-by-step explanation:
72-2/7 = 10
72-2=70
7X10=70
Answer:
10 ft
Step-by-step explanation:
Using the distance formula.