Draw the major organic product formed when the compound shown below undergoes a reaction with (ch3)2culi in diethyl ether, follo
wed by aqueous acid.
1 answer:
When the given alpha beta unsaturated carbony compound is treated with Organocuprate also called Gilman Reagent gives beta substituted carbonyl compound. As this reagent is soft nucleophile it adds to soft electrophile (beta carbon). Unlike Grignard Reagent which is hard nucleophile and adds to hard electrophile (carbonyl carbon) and produces corresponding alcohol. The reactions are as follow,
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200 mg of C₃₂H₃₄N₆O₁₀ contains 116 mg of carbon.
To obtain the answer to the question, we'll begin by calculating the molar mass of C₃₂H₃₄N₆O₁₀. This can be obtained as follow:
Molar mass of C₃₂H₃₄N₆O₁₀ = (12×32) + (1×34) + (14×6) + (16×10)
= 384 + 34 + 84 + 160
<h3>= 662 g/mol </h3>From the molar mass of C₃₂H₃₄N₆O₁₀, we can see that:
<h3>662 g of C₃₂H₃₄N₆O₁₀ contains 384 g of carbon. </h3>Converting 662 g of C₃₂H₃₄N₆O₁₀ to mg, we have
1 g = 1000 mg
Therefore,
662 g = 662 × 1000
<h3>662 g of C₃₂H₃₄N₆O₁₀ = 662000 mg</h3>Converting 384 g of carbon to mg, we have,
1 g = 1000 mg
Therefore,
384 g = 384 × 1000
<h3>384 g of carbon = 384000 mg</h3>Thus, we can say that:
662000 mg of C₃₂H₃₄N₆O₁₀ contains 384000 mg of carbon.
Finally, we shall determine the mass (in mg) of carbon in 200 mg of C₃₂H₃₄N₆O₁₀. This can be obtained as follow:
662000 mg of C₃₂H₃₄N₆O₁₀ contains 384000 mg of carbon.
Therefore, 200 mg of C₃₂H₃₄N₆O₁₀ will contain = = 116 mg of carbon.
Thus, we can conclude that 200 mg of C₃₂H₃₄N₆O₁₀ contains 116 mg of carbon.
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