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madam [21]
3 years ago
6

A water sample consists of the following cadmium species and their percentages of the total cadmium concentration: Cd2 (36 %); C

dHCO3- (14 %); CdCl- (25 %); and Cd(OH)2 (25 %). What percentage of Cd is toxic to aquatic organisms
Chemistry
1 answer:
Nata [24]3 years ago
5 0

Answer:

61%

Explanation:

Cd2+ and CD(OH)2 both contain the Cd2+ specie which is chemically similar to Zn2+both being in the same group in the periodic table. Cd2+ is know to be toxic when absorbed together with Zn 2+ ions and will definitely be toxic to the aquatic species.

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Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 14.0 atm. Calculate the work, w , if the gas exp
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Explanation:

6 0
3 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
3 years ago
Which of the following radiations consists of a helium nucleus emitted by some radioactive substances? Alpha radiation Beta radi
erica [24]

Answer: Alpha radiation

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_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\textrm{He}


Beta decay : When a larger radioactive nuclei decays into smaller nuclei by releasing beta radiation, the atomic number is increased by 1 unit.


_Z^A\textrm{X}\rightarrow _{Z+1}^{A}Y+_{-1}^0e


Gamma decay : When a larger radioactive nuclei decays into smaller nuclei by releasing gamma radiation, the mass number remains same.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

5 0
3 years ago
What mixture is it ?
joja [24]

The mixture should be

Heterogeneous

Explanation:

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7 0
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Is this statement true or false?
In-s [12.5K]

Answer:

true

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