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yan [13]
3 years ago
13

Why isn't the atomic mass of most of the elements on the Periodic Table an integer (not a decimal)?

Chemistry
1 answer:
elena55 [62]3 years ago
4 0

Answer:

Atomic mass is never an integer number for several reasons

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Pasteurization, vaccines against antrax and rabies, discovered the germ fermentation
7 0
3 years ago
Draw a physical model that shows the reaction of zinc metal and hydrochloric acid (hydrogen chloride).
Brilliant_brown [7]

Answer:

Zinc + Hydrochloric Acid Zinc Chloride and Hydrogen Gas

Zn + 2HCI - ZnCl2 + H2

Explanation:

Be sure to label your model to clearly show how you are representing the atoms

3 0
2 years ago
CaCo3+2HCL Cacl2+h2o+co2
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Answer:

Here

Explanation:

This is an acid-base reaction (neutralization): CaCO3 is a base, HCl is an acid.

6 0
3 years ago
A redox reaction employed in an electrochemical cell has a negative . Which statement is true? a) E∘cell is positive b) K>1 E
krok68 [10]

Answer:

d. K<1 E∘cell is negative

Explanation:

Since E⁰ = negative , ΔG = -nFE⁰ = -nF -ve = +ve.

Also, ΔG = -RTlnK

K = exp(-RTΔG)

Since ΔG = +ve, -RTΔG = -ve

K = 1/exp(RTΔG) < 1.

So our answer is  E⁰ cell is negative and K < 1

5 0
3 years ago
1. Sodium hydroxide reacts with carbon dioxide according to the equation: 2NaOH(s) + CO2(g) →
Leno4ka [110]

The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

<h3>What is Limiting reagent ?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Given chemical equation in balanced form ;

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).

According to the Chemical equation ;

  • The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

    If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.

    But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.

  • 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react

    As 80 g NaOH produces 106 g of Na₂CO₃.

    Therefore 5 g NaoH will produce ;

    106 / 80 x 5 = 6.625 g

Learn more about limiting reagent here ;

brainly.com/question/11848702

#SPJ1

5 0
2 years ago
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