Answer:
Theta has a reference angle of 30° and is in Quadrant I or II
Step-by-step explanation:
Sin(theta) = ½
Basic angle: 30
Angles:
30,
180-30 = 150
Because sin is positive in quadrants 1 and 2
Answer:
k = (6/15)
Step-by-step explanation:
The equation is:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
To have no solutions, we need to have something like:
x + 7 = x + 4
where we can remove x in both sides and end with
7 = 4
So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.
First, let's try to simplify our equation:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
6*x + 6 + 2 = 3*k*5*x + 3*1 + 3
6*x + 8 = 15*k*x + 6
if 15*k = 6, then the system clerly has no solution.
then:
k = 6/15
then we get:
6*x + 8 = (6/15)*15*x + 6
6*x + 8 = 6*x + 6
8 = 6
The system has no solutions.
If there are 24 hours a day, he hangs out 8 hours a day since 24-8-8=16
All activities are eqyal to 8/24, which simplifies to 1/3.
1/3 as a percent is 33.33...%
He should include 33.33..% three times in his circle graph.
Answer:
a. segment DE and segment EF are congruent to each other but not to segment DF, and their slopes are not related.
Step-by-step explanation:
In order for a triangle to be isosceles, two of the line segments must be congruent. (eliminates choices C and D)
If the slopes of the congruent segments are negative reciprocals of each other, the triangle is a right triangle, not an acute triangle. (eliminates choice B)
With choices B, C, D eliminated, we are left with choice A.
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However, <em>that necessary description is not sufficient</em> to constrain the triangle to be an acute triangle. In order for the triangle to be acute, the third side must be less than √2 times the length of either of the congruent sides.
The correct answer is "none of the above."
