1 ) B ) I<span>ntersections.
2 ) A ) Freeways ( i believe )
Matchmaking
-</span><span>Retractable STOP sign arm ( school bus )
-Jaywalking ( d</span><span>angerous pedestrian practice )
- Moped ( </span><span>cross between bicycle and motorcyble )
1 ) I would say the </span><span>major cause of collisions between cars and motorcycles is due to motorcycles driving into lane/places cars can not get into. - lane splitting, traffic jam -
2 )When there is a yeild sign or a crossing sign, it's </span><span>legal for a pedestrian to cross a roadway. ( I believe )
3)</span><span> Motorists must keep a constant lookout for pedestrians crossing and at intersections.
4) I know when trucks are driving up or anything similar they get faster and sometimes cant control, so there are certian stops that trucks go up to make them slow down. I honeslty don't know if you should go around or not. But i hope this helps.
</span>
The output will be: You owe $ 15.0
Answer:
#include <iostream>
#include<time.h>
using namespace std;
class Student
{
public :
int grades[20]; //array of grades
double average(int arr[],int n) //method to calculate average of array of grades passed
{
int sum=0;
for(int i=0;i<n;i++) //loop to calculate sum of all grades
sum=sum+arr[i];
return sum/n; //average is sum of items/number of items
}
int get_grade() //method to return grade number(1-14)
{
srand(time(NULL)); //method to generate different random number each time
int num = rand() % 14 + 1; //method to generate random number b/w 1-14
return num;
}
};
int main()
{
Student s;
int grade[]={5,3,9,8,10};
cout<<"Average is : "<<s.average(grade,5);
return 0;
}
OUTPUT :
Average is : 7
Explanation:
A class Student is created in which a method named average is there to calculate average of the grades passed and a method to generate a grade number b/w 1-14.
Answer:
The answer is "Option c"
Explanation:
Its the infrastructure used to upgrade, for it's upgrading it begins with improving its internet services, that require new routers, adapters, and modulation schemes, that arrive with smart detectors and functionaries, if it accidentally cut the cat 5e patch so, all the internet nodes shall be accessible except the server, and wrong choices can be described as follows:
- In option a, It is wrong because all network is not authenticated by the same server.
- In option b, Network nodes connection can be a switch, that's why is incorrect.
- Option d and Options e both were wrong because it is not divided on the same subnet and the printer is not available for all.
