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ki77a [65]
3 years ago
10

Let V=(2,8) and W=(-1,-4)

Mathematics
2 answers:
MArishka [77]3 years ago
6 0

Answer:

A.) The x-component of V is 2

B.) V= -2W

C.) V·W= -34

Tcecarenko [31]3 years ago
4 0

Answer:

B, and W are correct i think

Step-by-step explanation:

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The real root of the equation x3 – 7x2 + 15x – 25 = 0 is 5. What are the nonreal roots?
Elodia [21]

Answer:

1±2i.

Step-by-step explanation:

1. if to evaluate the expression given, it can be written

(x-5)(x²-2x+5)=0;

2. where the nonreal roots are 1±2i.

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2 years ago
Peggy had a bag of nuts. She ate 1/5 of the nuts and gave the remaining nuts to 3 friends equally. What fraction of the nuts did
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2.666666 u and left with 4/5 then divide that by 3
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440 callories in 4 servings; 300 serving in 3 servings
monitta
110 calories in the first one for ONE serving.

100 calories in the second one for ONE serving.

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STSN
6 0
4 years ago
Factor completely
luda_lava [24]

Answer:

B)

B)

D)

Step-by-step explanation:

1. 7x^3y+14x^2y^3-7x^2y^2

The GCF of all the term of the above polynomial is 7x^2y , hence we take it outside and form a bracket

7x^2y(x+2y^2-y)

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

2. 5x(x+3)+6(x+3)

The GCF of all the term of the above polynomial is (x+3) , hence we take it outside and form a bracket

(x+3)(5x+6)

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

3. 8x^5+2x^4+4x^2

The GCF of all the term of the above polynomial is 2x^2 , hence we take it outside and form a bracket

2x^2(4x^3+x^2+2)

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer

4 0
3 years ago
Which value of m will create a system of parallel lines with no solution? y=mx-6 8x-4y=12 A coordinate grid with one line labele
nydimaria [60]

Answer:

A system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2

Step-by-step explanation:

The equation of the given line is 8·x - 4·y = 12

Which gives;

8·x- 12= 4·y

y = 2·x - 3

Given that the line passes through the points (0, -3) and (1, -1), we have;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

When (x₁, y₁) = (0. -3) and (x₂, y₂) = (1, -1), we have;

Slope, \, m =\dfrac{(-1)-(-3)}{1-(0)} = 2

y - (-3) = 2×(x - 0)

y = 2·x - 3 which is the equation of the given line

For the lines 8·x - 4·y = 12, which is the sane as y = 2·x - 3 and the line y = m·x  - 6 to have no solution, the slope of the two lines should be equal that is m = 2

Given that the line passes through the point (1.5, 0), we have;

y - 0 = 2×(x - 1.5)  

y = 2·x - 3...................(1)

For the equation, y = m·x  - 6, when m = 2, we have;

y = 2·x  - 6..................(2)

Solving equations (1) and (2) gives;

2·x - 3 = 2·x  - 6, which gives;

2·x - 2·x=  - 3 - 6

0 = 9

Therefore, a system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2.

4 0
3 years ago
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