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3 years ago

Let V=(2,8) and W=(-1,-4)

Mathematics

2 answers:

MArishka [77]3 years ago

6 0

Answer:

A.) The x-component of V is 2

B.) V= -2W

C.) V·W= -34

Tcecarenko [31]3 years ago

4 0

Answer:

B, and W are correct i think

Step-by-step explanation:

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Can someone help me please

Margarita [4]

Answer:

Step-by-step explanation:

Solution :

Remember that the sum of complementary angles is always 90°.

First, finding the value of x :

Set up an equation :

( Being complementary angles )

Solve for x

{ Remove unnecessary parentheses }

{ Combine like terms }

{ Subtract 3 from 30 }

{ Move 27 to right hand side and change it's sign }

{ Subtract 27 from 90}

{ Divide both sides by 9 }

The value of X is 7°

Now, Replacing the value of x in order to find the value of B

{ Plug the value of x }

{ Multiply 7 by 7 }

{ Subtract 3 from 49 }

The measure of B is 46°

7 0

3 years ago

What X !!!!!!!!!!!!!!!!!! Help me please!!!!

Vaselesa [24]

Answer:

Step-by-step explanation:

According to the problem, 

45° + x = 180° [Linear pair]

=> x = 180° - 45°

=> x = 135° (Ans)

5 0

3 years ago

Read 2 more answers

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = Number of flights that arrive late.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$