Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Your answer is
B) 1/2
because there are 5 odd and 5 even numbers from 5 through 10, so it would be 1/2.
Glad I could help, and good luck!
Answer:
team loss after three games is 5.
Step-by-step explanation:
we will use positive sign for gain and negative sign for loss.
Given
Jim's team gained 7 yards on the first play
gain of yards = +7
lost 2 yards on the second play
loss of yards = -2
lost 10 yards on the third play
loss of yards = -10
Total yards gain or lost by Jim's team = +7 + (- 2) + ( - 10)
Total yards gain or lost by Jim's team = +7 -2 -10 = -5
sine sign is negative, it means there is loss and the net loss is 7 yards.
Thus, team loss after three games is 5.
Answer:
v=45
Step-by-step explanation:
I honestly don’t know wish I could help
