Answer:
y = 2
Step-by-step explanation:
I will solve this problem, using the elimination method.
-2(5x - 3y) = -11
-10x + 6y = 22
2x - 6y = -14
Subtract and divide for x
-8x = 8
x = -1
Input -1 into the equations
2(-1) - 6y = -14
-6y - 2 = -14
-6y = -12
y = 2
Thanks!
Thus, distribution is a function that shows the possible values for a variable and how often they occur and categorical values are summarized by counts and/or percents
In statistics, the distribution is a function that shows the possible values for a variable and how often they occur.
The distribution of a data set is the shape of the graph when all possible values are plotted on a frequency graph. Usually, we are not able to collect all the data for our variable of interest. Therefore we take a sample. This sample is used to make conclusions about the whole data set.
The categorical variable is a data in which individuals are placed into groups or categories.
One way to summarize categorical data is to simply count (frequency), or tally up, the number of individuals that fall into each category. Another way is to show the percentage of individuals who fall into each category, thereby creating a relative frequency.
Learn more about distribution here
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The answer is D. He divided both sides by 5 instead of dividing both sides by -5.
To find the area of the rectangle, do A=lw which is 4x13=52. to find the area of the triangle, first find the height. this is 13-6=7. now do A=bh/2 which is (5x7)/2=17.5. 17.5+52=69.5 which is your answer. DONT OPEN ANY LINKS ON HERE, ITS A VIRUS
Answer:
No, Angela is not correct.
As the method Jim was performing will also lead to the solution.
Step-by-step explanation:
We are given first equation as:
Ax + By = C
Second equation is:
Dx + Ey = F
Jim solved the equation as:
He begins by multiplying equation (1) by D and equation (2) by A.
and so by subtracting both the equations he will obtain a value of y.
and then put the y-value in any of the given two equations to obtain the value of x.
Angela Method:
you should have multiplied equation (1) by E and equation (2) by B.
and when she will subtract both the equations she will get the value of x first and then when she will put the value of x in any of the given equation she will obtain the value of y.
But both will get a value for x and y.
Hence, the method Jim was performing was also correct.
