We know that
Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19
the answer Part a) is 19
Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10
we know that
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34
the answer Part b) is -34
Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48
the answer Part c) is 48</span>
Answer:
he has 2 dollars
Step-by-step explanation:
10 * 10$= 1$
4 * 25$=1$
1$+1$=2$
Answer:
Step-by-step explanation:
The properties of circumcenter give that it lies at the midpoint of the hypotenuse if it is of a right triangle.
Now, the given triangle is a right triangle and the two ends of the hypotenuse WU are U(-3,2) and W(4,-3).
Therefore, the mid point of the hypotenuse WU will be given by 
.
Therefore, the circumcenter of the right triangle Δ UVW will be . (Answer)
Answer:
n = 17-13
Step-by-step explanation:
n+13=17
Subtract 13 from each side
n+13-13 = 17-13
n = 17-13
Answer:
Hope help
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