You must first set up an equation for this problem. Your equation is 8+3x=128. If we subtract 8 from each side we get 3x=120. If we then divide both sides by 3 we get x=40. Therefore your number is 40 because 8+3*40=128.
We have to break each degree in terms of 90
A) 
Which is in third quadrant, therefore sine is negative hence

B) 
Which is in third quadrant, therefore cosine is negative hence

C) 
Which is in third quadrant, therefore tangent is positive hence

D) 
Which is in third quadrant, therefore cosec is negative hence
not defined
E)
Which is in third quadrant, therefore secant is negative hence

F) 
Which is in third quadrant, therefore tangent is positive hence
not defined
Hence only
and
have value -1
Hope this will help
Answer:
i cant SEE the image
Step-by-step explanation:
Yeah you did well on the table
Subtract the like terms to get your answer of y^2 - 4y - 6