Answer:
0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches
Step-by-step explanation:
Mean trout length (μ) = 14 inches
Standard deviation (σ) = 3 inches
The z-score for any given trout length 'X' is defined as:
e interval
For a length of X =12 inches:

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.
For a length of X =18 inches:

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.
The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

Well, we know that 25% is also 1/4 and if we multiply $80.00 by 1/4 you get $20 so the answer is $20.
Hello There!
It is 4000.
Hope This Helps You!
Good Luck :)
- Hannah ❤
Answer:
-12
Step-by-step explanation:
We start with the equation: 
Substitute the variables: 
Solve using order of operations (start with multiplication): 
And then addition/subtration: 
I think its D. $1,800 because 10.4 multiplied by twelve is 124.8 and if you multiply that by 15 you get $1.872.