What is the solution to log3(x+12) = log3 (5x)?. X=-8 X=-3 N X=3 O X= 8

Which equation is true when x = 5? A 8x = 80 B x + 4 = 9 C 10 ÷ x = 5 D x − 6= 1

Pie

Answer:

B

Step-by-step explanation:

A. 8 * x = 80

8 * 5 = 40. 40 is not 80, so it doesn't work.

B. x + 4 = 9

5 + 4 = 9. This works.

C. 10 ÷ x = 5

10 ÷ 5 = 2. 5 is not 2, so it doesn't work.

D. x - 6 = 1

5 - 6 = -1. 1 is not -1, so it doesn't work.

5 0

2 years ago

Use the counting techniques from the last chapter. A bag contains three red marbles, four green ones, one fluorescent pink one,

sergiy2304 [10]

Answer:

The probability that she gets all the red ones, given that she gets the fluorescent pink one, is P=0.0035 or 0.35%.

Step-by-step explanation:

Susan grabs four marbles at random.

We have to calculate the probabilities that he picks the 3 red ones, given that she already picked the fluorescent pink.

If it is given that the fluorescent pink is already picked, we are left with three red marbles, four green ones, two yellow ones, and four orange ones. A total of 13 marbles.

The probability that the second marble is red is 3 in 13.

The probability that the third marble is also red is 2 (the red marbles that are left) in 12 (the total amount of marbles left), as there is a picking without replacement.

The probability that the fourth marble is 1 in 11.

Then, the probability that the 3 red marbles are picked, is:

$P=P_1\cdot P_2\cdot P_3=\dfrac{3}{13}\cdot \dfrac{2}{12}\cdot \dfrac{1}{11}=\dfrac{6}{1716}=0.0035$

4 0

3 years ago

Standard issue passenger license plates in Ohio consist of three letters followed by four numbers. How many standard issue licen

dezoksy [38]

Answer:

The standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 175760000

Step-by-step explanation:

If there are no restrictions, all numbers and letters are available to be used then. And with no restrictions, every number or letter can appear more than once.

There are 7 spaces available; 3 spaces for letters, 4 spaces for numbers

The different combination of letters and numbers then becomes,

26 × 26 × 26 × 10 × 10 × 10 × 10

This is because, all 26 letters (A to Z) can occupy the first space, the second space and the third space. And all 10 digits (0 to 9) can occupy the fourth space, the fifth space, the sixth space and the seventh space.

So, the standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 26 × 26 × 26 × 10 × 10 × 10 × 10 = 175760000 different standard issue license plates.

8 0

3 years ago

What is the distance between R(5,2) and S(4,-7)? Round to the nearest tenth.

Naddik [55]

You can calculate the distance between two point using this fomula:

√(x_2-x_1)^2+(y_2-y_1)^2

If you insert you values you get:

√(4-5)^2+(-7-2)^2 = 9.06 = 9.1

5 0

3 years ago

Steps to solve this equation 25 1/7- 12 5/7=

alex41 [277]

$\frac{25*7+1}{7} - 12 \frac{5}{7}
 
$

$\frac{175+1}{7} - 12 \frac{5}{7}$ $\frac{176}{7} - \frac{12*7+5}{7}$

4 0

4 years ago