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Wittaler [7]
3 years ago
12

(a,1/b) and (b,1/a) find the slope of the line joining the points whose coordinates are

Mathematics
1 answer:
pogonyaev3 years ago
6 0

Answer:

m=\frac{1}{ab}

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the points

(a,1/b) and (b,1/a)

substitute

m=\frac{1/a-1/b}{b-a}

m=\frac{\frac{b-a}{ab}}{b-a}

m=\frac{1}{ab}

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Gelneren [198K]
V=LWH
SA=2(LW+LH+WH)
V=240
first check that they are 240 volume
multiply numbers they should equal 240

the first one (A) can be eliminated since the dimentions are the same and therefor the surface areas are the same

2nd one check so far

3rd one (C) 6*4*15=360 which is wrong so eliminate this one

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answer is B
3 0
3 years ago
If the right side of the equation dy dx = f(x, y) can be expressed as a function of the ratio y/x only, then the equation is sai
melomori [17]

Answer:

 y = x*sqrt(Cx - 1)

Step-by-step explanation:

Given:

                                  dy / dx = (x^2 + 5y^2) / 2xy

Find:

Solve the given ODE by using appropriate substitution.

Solution:

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                               dy/dx = 0.5(x/y) + 2.5(y/x)

- use substitution y = x*v(x)

                               dy/dx = v + x*dv/dx

- Combine the two equations:

                                v + x*dv/dx = 0.5*(1/v) + 2.5*v

                                x*dv/dx = 0.5*(1/v) + 1.5*v

                                x*dv/dx = (v^2 + 1) / 2v

-Separate variables:

                                 (2v.dv / (v^2 + 1) = dx / x  

- Integrate both sides:

                                 Ln (v^2 + 1) = Ln(x) + C

                                 v^2 + 1 = Cx

                                 v = sqrt(Cx - 1)

- Back substitution:

                                (y/x) = sqrt(Cx - 1)

                               y = x*sqrt(Cx - 1)

                         

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Answer:

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Step-by-step explanation:

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