The edge length of the cube is 0.4
The closest to the maximum number of cups the punch bowl can hold is 30
<h3>How to determine the number of cups?</h3>
The given parameters are:
1 cup = 15 cubic inches
Diameter of bowl, d = 12 inches
The radius is the half of the diameter.
So, we have:
r = 6
The volume of the bowl is then calculated using:
This gives
Evaluate
V = 452.16
The maximum number of cups is then calculated using:
Cups = 452.16/15
Evaluate
Cups = 30.1444
Approximate
Cups = 30
Hence, the closest to the maximum number of cups the punch bowl can hold is 30
Read more about volumes at:
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The student went wrong in step three. the solutions should have been -3 and 5
Answer:
Range = (237100, 292900)
Step-by-step explanation:
Using Chebyshevs Inequality:
Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ ± kσ
where;
μ = 265000
σ = 9300
Range = 265000 ± 3(9300)
Range = 265000 ± 27900
Range = (265000 - 27900, 265000 + 27900)
Range = (237100, 292900)