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2 years ago

I really need help on this, how do you get 20 as a denominator and 19 as a numerator in the end answer? Pls help

Mathematics

2 answers:

valentina_108 [34]2 years ago

7 0

Answer:

ADD them

Step-by-step explanation:

11 1/5+ 5 1/4 is 19/20

If you were subtracting the fractions your answer would be different (look at attachment)

Lostsunrise [7]2 years ago

5 0

Answer:

To find the difference of the weights, you must subtract the smaller number from the bigger number.

First, we want to convert both mixed numbers to improper fractions

5 1/4 = 20/4 + 1/4 = 21/4

11 1/5 = 55/5 + 1/5 = 56/5

Now, we make the denominator for both to be equal to 20, and subtract to get the answer: 119/20, or about 5.95 pounds.

Let me know if this helps!

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4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

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Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

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Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

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$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

7 0

1 year ago

Equation A: a=5b + 1

lukranit [14]

ANSWER:

a = 11

b = 2

Explaination:

We have two equations:

a = 5b + 1 .....................(1)

a = 3b + 5.....................(2)

Here we use substitution method in order to solve the set of equations.

put a=3b+1 to equation (1)

3b + 5 = 5b + 1

Solve for b

5 = 5b -3b + 1

5-1 =2b

4 = 2b

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Now put the value of b = 2 into the equation (1) or (2)

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a = 5(2) + 1

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3 years ago