I’m not sure if this helps, but the area of a hexagon with a perimeter of 12 inches would be 10.39 inches squared
Step-by-step explanation:
Lets assume that angle of right angle trangles are <a,<b and <c
here one of the angle is 90°
so, <a=90°
now,
By the question
<c=3×<b+14
again,
<a+<b+<c=180° (being sum of interior angles of trangles)
90°+<b+(3×<b+14)=180° ( including the value of <a and <c)
90°+<b+3<b+14=180°
4<b=180-90-14
<b=86/4
<b=19°
<c=3×<b+14
=3×19+14
<c=71
smallest angle is 19°
and another small angle is 71°
24.5=-2.5c-4c
24.5=-6.5c
49=-13c
3.77=-c
c=-3.77
Answer:
no solution
Step-by-step explanation:
1. since the equations equal each other
2x+19=x+7
-x -x
x+19=7
-19 -19
x= -12
sub into y= x+7
y= -12+7
y= -5
2. x+2y=-7
<span>x+y+23=0
i don't know what the second equation is equal to, i'll assume 0
2y=x-7
y=1/2x-7/2
sub this into x+y+23=0
x+1/2x-7/2+23=0
3/2x+39/2=0
-39/2 -39/2
3/2x= -39/2
x=-39/2 / 3/2
x= -13
sub into y=1/2x-7/2
y=1/2(-13)-7/2
y= -10
3. </span>x+5y=2
<span>x=-4y+5
</span>sub x=-4y+5 into x+5y=2
-4y+5+5y=2
y+5=2
-5 -5
y= -3
sub y =-3 into x =-4y+5
x=-4(-3)+5
x= 17
4. 3x+y=9
<span>y=-5x+9
</span>sub -5x+9 into 3x+y=9
3x+(-5x+9)=9
3x-5x+9=9
-2x+9=9
-9 -9
-2x=0
x=0
sub into y=-5x+9
y=-5(0)+9
y=9
