Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
t = (ln [y(t) ÷ a]) ÷ -k (we can say beginning amount = 200 and ending amount = 100
t = (ln [200 ÷ 100]) ÷ -k
t = (ln [2]) ÷ -k
t = 0.69314718056 ÷ --.03
t = 23.1049060187 
about 23 years

7 0

2 years ago

Read 2 more answers

Plese i need help on this one !!!!!!!

patriot [66]

Answer:

I got 32.

Step-by-step explanation:

I used the Pythagorean theorem to find the lengths of the width and length. The length between (-1, 4) and (3, 3) was approximately 4 in. The distance between (-1, 4) and (-3, -4) was approximately 8 in. I then used those numbers to find the perimeter ((2*4)+(2*8))

8 0

3 years ago

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Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago

Help please I need help with this asap

solniwko [45]

Answer:

The answer is A.

Step-by-step explanation:

Hope fully this helps.

4 0

2 years ago

What is the quotient of 3.201 x 109 and 4.85 x 103 expressed in scientific notation?​

What is the quotient of 3.201 x 109 and 4.85 x 103 expressed in scientific notation?