For the answer to the question above,
1. If we let x as the side of the square cut-out, the formula for the capacity (volume) of the food dish is:
V = (12 - 2x)(8 - 2x)(x)
V = 96x - 40x^2 + 4x^3
To find the zeros, we equate the equation to 0, so, the values of x that would result to zero would be:
x = 0, 6, 4
2. To get the value of x to obtain the maximum capacity, we differentiate the equation, equate it to zero, and solve for x.
dV/dx = 96 - 80x + 12x^2 = 0
x = 5.10, 1.57
The value of x that would give the maximum capacity is x = 1.57
3. If the volume of the box is 12, then the value of x can be solved using:
12 = 96x - 40x^2 + 4x^3
x = 0.13, 6.22, 3.65
The permissible value of x is 0.13 and 3.65
4. Increasing the cutout of the box increases the volume until its dimension reaches 1.57. After that, the value of the volume decreases it reaches 4.
5. V = (q -2x) (p - 2x) (x)
T-v
7-(-3)
7+3
10
the answer is 10
B = {a, b, c, d}
C = {0, a, 2, b}
B ∪ C = {a, b, c, d, 0, 2}
<h3>Answer: E)</h3>
Everything from the set B and everything from the set C give to one set. Duplicated elements are written only once.
The table tells you that f(x)=0 at x=-6 and -2
<span>The limousine will cost $240.
$180 for the first three hours, plus 30 for each hour after. They need two extra hours.
So, 180+30(2)=240.
They also want to leave a $20 dollar tip.
So, 240+20=260
That is $260 dollars they need to pay altogether.
Divide that number by the number of students and you'll get how much they each must pay.
260/8=32.50
$32.50 each.
♦Brainliest please♦
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