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velikii [3]
4 years ago
9

In the similar triangle ABE and triangle CDE,AB=10cm,ED=4cm,CD=8cm find the length of BC​

Mathematics
1 answer:
Ostrovityanka [42]4 years ago
3 0

9514 1404 393

Answer:

  BE = 5 cm

Step-by-step explanation:

Your problem statement asks for the length of BC. There is no segment BC. Points B and C are in different triangles.

The length of segment BE can be found from the proportion ...

  BE/DE = AB/CD

  BE = DE·AB/CD = (4 cm)(10/8)

  BE = 5 cm

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Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x 2. What is the function’s vertex? (one-half, seven-
nydimaria [60]

Vertex of the quadratic equation is the highest or the lowest point of the quadratic equation.

<h3>Given-</h3>

The given equation in the question is,

f(x) = x^2 - x +2

<h3>Vertex of the quadratic equation</h3>

Vertex of the quadratic equation is the highest or the lowest point of the quadratic equation.

To find the vertex of the equation we need to compare the given equation with the following equation.

f(x)=a(x-h)^2+k

Here h and k are the vertex of the equation.

The given equation is,

f(x) = x^2 - x +2

Rewrite the equation,

f(x) = x^2 - x +(\dfrac{1}2)^2} +2-(\dfrac{1}2)^2}

f(x) = x^2 - x +\dfrac{1}{4} +2-\dfrac{1}4}

f(x) =(x-\dfrac{1}{2} )(x-\dfrac{1}{2} )+2-\dfrac{1}{4}

f(x) =(x-\dfrac{1}{2} )^2+\dfrac{7}{4}

Thus the vertex of the quadratic equation is 1/2 and 7/4.

Learn more about the vertex of the quadratic equation here;

brainly.com/question/6356924

3 0
3 years ago
3z + 2 + (-5) + 6 PLS HELP NEED TO TURN IN BY 2:30
Ostrovityanka [42]

Answer:

ok, but what does z in the equation equal? Since its a letter it has to equal to a number

5 0
3 years ago
D too btw it just cut off
kicyunya [14]

Answer:

wha do you mean

Step-by-step explanation:

8 0
3 years ago
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djverab [1.8K]

Answer:

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Step-by-step explanation:

If you subtract the 2 from the y+2 and from the simplified version of 2/3(4), you get the answer above! I hope this helps!

4 0
3 years ago
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