2 years ago

There is approximately 0.455 kilogram in 1 pound. How many pounds are in 9 kilograms?

Mathematics

1 answer:

Monica [59]2 years ago

3 0

Answer:

19.84 I'm pretty sure

Step-by-step explanation:

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Determine the truth value of the given conditional statement

seraphim [82]

Answer: A false statement implies a true statement, so the conditional statement is true

Step-by-step explanation:

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2 years ago

I’ll give Brainlest<br><br> m m m

JulijaS [17]

Answer:

steps below

Step-by-step explanation:

arc QR = 2x57 - 41 = 73

arc PQ = 360 - 73 - 41 - 137 = 109

m∠Q = (41+137) / 2 = 89°

m∠R = (109+137) / 2 = 123°

m∠S = (109+73) / 2 = 91°

check: ∠R+∠p = 123+57 = 180

∠Q+∠S = 89+91 = 180

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2 years ago

10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135

Viefleur [7K]

The simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

First we must simplify the expression:
$\frac{3 \sqrt{160} }{\sqrt{1350x} } = \frac{12 \sqrt{10} }{15 \sqrt{6x} } = \frac{4 \sqrt{10} }{5 \sqrt{6x} }$

Then we factor the rational parts and cancel it out:
$\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }$

Then we rationalize the expression:
$\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}$

<span>Finally, the simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .</span>

7 0

2 years ago

in one month darius spends 10 hours walking dogs. How many dogs walks does he do in one month ALSO this is dividing a whole numb

MA_775_DIABLO [31]

Step-by-step explanation:

let's assume one month is 30 days you would multiply 10 by 30.

$10 \times 30 = 300$