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ZanzabumX [31]
3 years ago
13

Can rectangular prism and a cube have the same volume

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
No because it has to be the same length and width in another way it would be equal for both shapes
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Amy, Doug, and Ginger took a math test. Amy scored 12 points higher than Doug, and Ginger scored twice as many points as Doug. T
lakkis [162]
Amy(A): D + 12
Doug(D):D
Ginger(G):2D
SumOfAll(S)=208 : Total points / sum of all three friends

(D+12)+D+2D=208
D+12+3D=208 - transpose 12 to the right side
4D=208-12 
4D = 196   - divide both sides by 4
D=49
Therefore, Doug scored 49

7 0
3 years ago
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Is y – 4x = 9 a function?
Alex787 [66]
No i don’t think soooo

5 0
3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
4 +y = 12. Substitute 8 for x.
Alexeev081 [22]

Answer:

where should I substitute 8 for x? if its like this 4(8)+y=12 than its y=-20

Step-by-step explanation:

8 0
3 years ago
Changle. Show all work. Round each length to the nearest tenth and each angle to the
Sedaia [141]

Answer:

Part 1) BC=12.2\ units

Part 2) m\angle A=55^o

Part 3) m\angle C=35^o

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=7^2+10^2

AC^2=149\\AC=12.2\ units

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

tan(A)=\frac{BC}{AB} ----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{10}{7}

using a calculator

m\angle A=tan^{-1}(\frac{10}{7})=55^o

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

m\angle A+m\angle C=90^o ----> by complementary angles

substitute the given value

55^o+m\angle C=90^o

m\angle C=90^o-55^o=35^o

8 0
3 years ago
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