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dimaraw [331]
3 years ago
6

Can someone really help me please

Mathematics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

1-B, 2-B, 3-B, 4-B, 5-A

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What is the measure of x?
UkoKoshka [18]

Answer:

x=4

Step-by-step explanation:

(whole secant) x (external part) = (tangent)^2

(x+5) *x = 6^2

x^2 +5x = 36

Subtract 36 from each side

x^2 +5x - 36 = 0

Factor

( x-4) (x+9) = 0

Using the zero product property

x-4 = 0  x+9 =0

x = 4  x=-9

Cannot be negative since that is negative length

x=4

7 0
3 years ago
Can someone help me
Alexxandr [17]

Answer:

i) 0.1056

ii) 0.105

iii) 0.1

iv) 0.1056

Step-by-step explanation:

0.36, to the power of 2 (0.36×0.36) is 0.1296

0.1296-0.03×0.8=0.1056

6 0
2 years ago
Multiply to -260 add to 7
djyliett [7]
What can you be more specific like a put it in a sentence. For example x*-260+7=?

6 0
3 years ago
Write the standard equation of the circle below.
s344n2d4d5 [400]

Answer:

The first answer is correct.

(x + 1)^2 + (y - 2)^2 = 1

A circle with the midpoint M(Mx, My) and the radius r can be written as

(x - Mx)^2 + (y - My)^2 = r^2


7 0
4 years ago
A population of 1,500 insects grows exponentially by a factor of 3 every week. Select all equations that represent or approximat
Andreas93 [3]

Answer:

FV(p)= PV*(1 + g)^t

Step-by-step explanation:

Giving the following information:

Number of insects (PV)= 1,500

Increase rate= 3 weekly

<u>First, we need to calculate the daily growth rate:</u>

Daily rate (g)= [3^(1/7)] - 1

Daily rate (g)= 0.16993

<u>Now, by using the following formula, we can determine the population p in any given day t:</u>

FV(p)= PV*(1 + g)^t

<u>For, example after 7 days:</u>

FV(p)= 1,500*(1.16993^7)

FV(p)= 4,500

<u>For example, after 10 days:</u>

FV(p)= 1,500*(1.16993^10)

FV(p)= 7,206

4 0
3 years ago
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