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IgorC [24]
3 years ago
12

Find the distance of each the following lines from the origin.

Mathematics
1 answer:
meriva3 years ago
7 0

Answer:

Step-by-step explanation:

3x+y−7=0 and x+2y+9=0

write in the form y=mx+c

i.e.y=−3x+7,y=  

2

−x

​  

−  

2

9

​  

 

∴m  

1

​  

=−3 and m  

2

​  

∓−  

2

1

​  

 

tan(A−B)=  

∣

∣

∣

∣

∣

​  

 

1+tanAtanB

tanA−tanB

​  

 

∣

∣

∣

∣

∣

​  

 

∣

∣

∣

∣

∣

​  

 

1+(−3)(−y  

2

​  

)

−3−(−y  

2

​  

)

​  

 

∣

∣

∣

∣

∣

​  

 

=  

∣

∣

∣

∣

∣

​  

 

5/2

−5/2

​  

 

∣

∣

∣

∣

∣

​  

=1

∴ Angle b/w then is tan  

−1

(1)=45  

∘

 

=  

4

π

​

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1234
hodyreva [135]

Answer:

1) 2

2) 4

3) 3

4) 1

Step-by-step explanation:

8/4 is 2

8/2 is 4

3/1 is pretty simply 3

And lastly (and kind of least)...

3/3 is 1

Hope this helped you out!

8 0
2 years ago
Least common multiple of 9 45 and 81
WITCHER [35]
<span>The lowest common multiple is the smallest number that is a shared multiple of a set of numbers. 9 x 1 = 9, 9 x 5 = 45 and 9 x 9 = 81. The smallest common multiple is 9.</span>
5 0
4 years ago
Which solid has two bases that are triangles and three lateral surfaces that are rectangles?
arlik [135]
Answer is triangular prism.

Pyramids have only 1 bases so they cannot be the answer. Prisms on the other hand have 2 bases. Prism sides are rectangles no matter of the shape of the bases.  In the text of the task it is required that bases are triangles therefore rectangular pyramid cannot be the answer.

Correct answer is triangular prism.
5 0
3 years ago
4(b-1)=2b+10 what is the value of b in this equation
andriy [413]
4(b-1)=2b+10  carry out indicated multiplication on the left side

4b-4=2b+10  subtract 2b from both sides

2b-4=10  add 4 to both sides

2b=14 divide both sides by 2

b=7
3 0
4 years ago
Solve for t. Express your answer in simplest and exact form.
Masteriza [31]

Answer:

t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))

Step-by-step explanation:

Solve for t:

z = (h t^2)/2 + t q_1

z = (h t^2)/2 + t q_1 is equivalent to (h t^2)/2 + t q_1 = z:

(h t^2)/2 + t q_1 = z

Divide both sides by h/2:

t^2 + (2 t q_1)/h = (2 z)/h

Add q_1^2/h^2 to both sides:

t^2 + (2 t q_1)/h + q_1^2/h^2 = (2 z)/h + q_1^2/h^2

Write the left hand side as a square:

(t + q_1/h)^2 = (2 z)/h + q_1^2/h^2

Take the square root of both sides:

t + q_1/h = sqrt((2 z)/h + q_1^2/h^2) or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)

Subtract q_1/h from both sides:

t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)

Subtract q_1/h from both sides:

Answer: t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))

8 0
3 years ago
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