A cylinder is sliced perpendicular to its circular base. What shape will the cross section be?
2 answers:
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The <u>equation</u>
consists of five <u>terms</u>, three of them contain <u>fractions.</u> The <u>denominators</u> of these fractions are 2, 4 and 6.
Find the LCM(2,4,6). Since
- 2=2;
- 4=2·2;
- 6=2·3,
then LCM(2,4,6)=2·2·3=12.
Thus, you have to multiply each term of the equation by 12 to eliminate the fractions.
Answer: 12