On average, cody runs 4 miles in 38 minutes. How fast should he plan to run a 10-mile race if he maintains this place.

Translate the figure 5 units up. Then decide if each statement about translated figures is true or false,

m_a_m_a [10]

Answer:

First, second, and third are true.

Fourth is false.

Step-by-step explanation:

1. When we're translating a figure, everything about the figure stays the same except its location on the coordinate plane. The side lengths, the angle measures, and parallel sides will not change.

2. The fourth one is false because two figures/objects are congruent if they have the same shape and size. Since translation only affects the location on a coordinate plane, the original and final figure are congruent.

5 0

3 years ago

Luke shaded 20 squares on his hundredths grid. Bekka shaded 30 squares on her hundredths grid. Write two decimals greater than L

Rus_ich [418]

Luke's original decimal is 0.20 and Bekka's is 0.30 so 0.40 and 0.50 would be greater than Luke's original and 0.20 and 0.10 are lesser than Bekka's original decimal

5 0

3 years ago

Read 2 more answers

(6, –3) and (6, –11) (6, –5) and (6, –9) (10, –7) and (2, –7) (8, –7) and (4, –7)

ivolga24 [154]

i really appreciate this post you are the real mvp

3 0

3 years ago

Find the value of x in the triangle shown below<br><br>HELP ASAP!!!!!

tiny-mole [99]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷ Since this is an isoceles triangle, you can figure it out easily.

We know that the sum of the angles is 180 degrees.

180-56=124

124/2=62

X=62

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

5 0

3 years ago

Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out o

Nuetrik [128]

We have the function

$p(t)=550(1-e^{-0.039t})$

Therefore we want to determine when we have

$p(t_0)=550$

It means that the term

$e^{-0.039t}$

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

$e^{-0.039t}\rightarrow0$

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

$\alpha=\frac{1}{0.039}$

The inverse of the number, but why do that? look what happens when we do t = α

$e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}$

And when t = 2α

$e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}$

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

$e^{-0.039t}\approx0$

Only using powers of e

Let's write some inverse powers of e:

$\begin{gathered} \frac{1}{e}=0.368 \\ \\ \frac{1}{e^2}=0.135 \\ \\ \frac{1}{e^3}=0.05 \\ \\ \frac{1}{e^4}=0.02 \\ \\ \frac{1}{e^5}=0.006 \end{gathered}$

See that at t = 5α we have a small value already, then if we input p(5α) we can get

$\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550\cdot0.994 \\ \\ p(5\alpha)\approx547 \end{gathered}$

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

$\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\ \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}$

7 0

1 year ago